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Leya [2.2K]
2 years ago
13

I need help please ):

Mathematics
2 answers:
Inga [223]2 years ago
7 0
If you want me to tell you the answer I need more points
rjkz [21]2 years ago
4 0

Answer:

100

Step-by-step explanation:

multiply in the formula

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The ratio of students to teachers is 2:3 respectively.If there are 21 teachers, how many students are there?
yulyashka [42]

Answer:14


Step-by-step explanation:

2:3

14:21

in 14 their is 2 7's

in 21 their is 4 7's


6 0
3 years ago
McDonald's is the king of the burger world, as it has more hamburger joints than any other restaurant chain. In 2013, McDonald's
Harlamova29_29 [7]

The notation per capita simply means that the number is divided by the total population. Therefore the number of McDonald’s per capita in Canada 2013 is:

McDonald’s per capita = 1427 / 35,160,000

<span>McDonald’s per capita = 4.06 x 10^-5</span>

6 0
3 years ago
{c(1) = 3/16<br> {c(n)=c(n−1)⋅4<br> ​ <br><br> what is the 3rd term in this sequence?
mote1985 [20]

Answer:

\large\boxed{c(3)=3}

Step-by-step explanation:

\left\{\begin{array}{ccc}c(1)=\dfrac{3}{16}\\\\c(n)=c(n-1)\cdot 4\end{array}\right

Put n = 2 and next n = 3 to the recursive formula:

c(2)=c(2-1)\cdot4=c(1)\cdot4\to c(2)=\dfrac{3}{16}\cdot4=\dfrac{3}{4}\\\\c(3)=c(3-1)\cdot4=c(2)\cdot4\to c(3)=\dfrac{3}{4}\cdot4=3

4 0
3 years ago
Complete the tables of values.<br> x 4−x<br> −1 4<br> 0 a<br> 2 b<br> 4 c
Alchen [17]

Answer:

12

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
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