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2 years ago

I need help please ):

Mathematics

2 answers:

Inga [223]2 years ago

7 0

If you want me to tell you the answer I need more points

rjkz [21]2 years ago

4 0

Answer:

100

Step-by-step explanation:

multiply in the formula

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The ratio of students to teachers is 2:3 respectively.If there are 21 teachers, how many students are there?

yulyashka [42]

Answer:14

Step-by-step explanation:

2:3

14:21

in 14 their is 2 7's

in 21 their is 4 7's

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3 years ago

McDonald's is the king of the burger world, as it has more hamburger joints than any other restaurant chain. In 2013, McDonald's

Harlamova29_29 [7]

The notation per capita simply means that the number is divided by the total population. Therefore the number of McDonald’s per capita in Canada 2013 is:

McDonald’s per capita = 1427 / 35,160,000

McDonald’s per capita = 4.06 x 10^-5

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3 years ago

{c(1) = 3/16 {c(n)=c(n−1)⋅4 what is the 3rd term in this sequence?

mote1985 [20]

Answer:

$\large\boxed{c(3)=3}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}c(1)=\dfrac{3}{16}\\\\c(n)=c(n-1)\cdot 4\end{array}\right$

Put n = 2 and next n = 3 to the recursive formula:

$c(2)=c(2-1)\cdot4=c(1)\cdot4\to c(2)=\dfrac{3}{16}\cdot4=\dfrac{3}{4}\\\\c(3)=c(3-1)\cdot4=c(2)\cdot4\to c(3)=\dfrac{3}{4}\cdot4=3$

4 0

3 years ago

Complete the tables of values. x 4−x −1 4 0 a 2 b 4 c

Alchen [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago