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irga5000 [103]
2 years ago
7

SHOW ALL WORK AND INCLUDE UNITS

Chemistry
1 answer:
Sunny_sXe [5.5K]2 years ago
3 0

Answer:

345J

Explanation:

-mass of iron (m) = 10.0 g

-temperature (ΔT) = final temperature- initial temperature= 100-25=  75 degree Celsius

-Specific Heat capacity of iron (c)= 0.46J/g°C.

Heat (Q)=?

Solution:

Formula for Heat is :

Q=m x c x ΔT

Q= 10 x 0.46 x 75

Q= 345 J.  

so, 345 joules of heat are needed to increase the temperature of 10 grams of iron.

From the above formula, all other questions can easily be solved from the same procedure.

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Answer:

Final temperature = 1279.25 K

Explanation:

We can solve this using the formula for Charles law since we are given volume and temperature.

From Charles law, we know that;

V1/T1 = V2/T2

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A vessel of volume 22.4 dm3 contains 2.0 mol h2 and 1.0 mol n2 at 273.15 k initially. all the h2 reacted with sufficient n2 to f
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Volume = 22.4 dm3
n = 2 mol of H2
n = 1 mol of N2
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PH2 = 0
PN2 = 1/3*0.0999924 = 0.0333308 atm
PNH3 = 2/3*0.0999924 = 0.0666616 atm
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