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irga5000 [103]
3 years ago
7

SHOW ALL WORK AND INCLUDE UNITS

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

345J

Explanation:

-mass of iron (m) = 10.0 g

-temperature (ΔT) = final temperature- initial temperature= 100-25=  75 degree Celsius

-Specific Heat capacity of iron (c)= 0.46J/g°C.

Heat (Q)=?

Solution:

Formula for Heat is :

Q=m x c x ΔT

Q= 10 x 0.46 x 75

Q= 345 J.  

so, 345 joules of heat are needed to increase the temperature of 10 grams of iron.

From the above formula, all other questions can easily be solved from the same procedure.

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The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur
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Answer:

the activation energy Ea = 179.176 kJ/mol

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Explanation:

From the given information

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b)

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T_2 = 386 \  K  \\ \\T_1 = (89.8 + 273)K = 362.8 \ K

In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})

In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})

In (\dfrac{R_2}{R_1}) = 0.00357

\dfrac{R_2}{R_1}= e^{0.00357}

\dfrac{R_2}{R_1}= 1.0035

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R_2 = \dfrac{1}7{}

R_1 = \dfrac{1}{t}

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\dfrac{t}{7}= 1.0035

t = 7.0245 mins

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