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2 years ago

Do the chemical bonds between atoms change during cellular respiration?

1 answer:

6 0

During cellular respiration, the carbon and hydrogen atoms change partners and bond with oxygen atoms instead. The carbon-hydrogen bonds are replaced by carbon-oxygen and hydrogen-oxygen bonds. As the electrons of these bonds "fall" toward oxygen, energy is released.

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34. An electron in the 3d state of the hydrogen atom has a radial part of the wave function of the form A r2 exp(-r/3ao). What i

nikdorinn [45]

Answer: Option (e) is the correct answer.

Explanation:

Formula to calculate radius is as follows.

p(r) = $Ar(r^{2}e^{\frac{-r}{3a_{o}}}$

= $Ar^{3}e^{\frac{-r}{3a_{o}}}$

$\frac{dp(r)}{dr}$ = 0

$Ar^{3}e^{\frac{-r}{3a_{o}}}(\frac{-1}{3a_{o}}$ + $Ae^{\frac{-r}{3a_{o}}}(3r^{2})$ = 0

$\frac{Ar^{3}}{3a_{o}}e^{\frac{-r}{3a_{o}}}$

= $3Ar^{2}e^{\frac{-r}{3a_{o}}}$

r = $9a_{o}$

Thus, we can conclude that most likely radius at which the electron would be found is $9a_{o}$ .

4 0

3 years ago

The monatomic ions of Groups 1A(1) and 7A(17) are all singly charged. In what major way do they differ? Why?

insens350 [35]

Answer: Group 1 ions are known as cations and Group 17 ions are known as anions.

Explanation:

Ions are formed when an atom looses or gains electrons.

If an atom gains electrons, it leads to the formation of negative ions known as anions. For Example: Fluorine is a Group 17 element which gains 1 electron to form $F^-$ ions.

If an atom looses electrons, it leads to the formation of positive ions known as cations. For Example: Sodium is a Group 1 element which looses 1 electron to form $Na^+$ ions.

Hence, group 1 ions are known as cations and Group 17 ions are known as anions.

3 0

3 years ago

Read 2 more answers

5.58e-18 + 8.65e-13 / -8.76e+06

evablogger [386]

Answer:

this is the answer:

− 10.13099839

Explanation:

5 0

3 years ago

How many grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5g of na2s and

tangare [24]

The reaction between Na2S and CuSO4 will give us the balanced chemical reaction of,
Na2S + CUSO4 --> Na2SO4 + CuS
This means that for every 78g of Na2S, there needs to be 159.6 g of CuSO4. The ratio is equal to 0.4887 of Na2S: 1 of CuSO4. Thus, for every 12.1g of CuSO4, we need only 5.91 g of Na2S. Thus, there is an excess of 9.58 g of Na2S. The answer is letter C.

8 0

3 years ago

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Three parts of an atom

ehidna [41]

Answer:

the atom can be broken down into three constituents parts – protons, neutron, and electrons.

Explanation:

Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge.

5 0

3 years ago

Read 2 more answers