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Zepler [3.9K]
3 years ago
9

Look at 3 or 4 other atoms using the simulation. Do any of them ahve a whole number for atomic mass?

Chemistry
1 answer:
In-s [12.5K]3 years ago
7 0

Answer:

There are three isotopes of silicons. They have masses numbers of 28, 29 and 30. The average amount of silicons is 28.086alum

Explanation:

I learned this in class three days ago so I hope this is helpful i'm in high school  ask me for help when ever you want Iĺl help you

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Convert 35 mL to cm3. 1 mL = 1 cm3
ivann1987 [24]
It’s still 35cm3
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3 years ago
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Shtirlitz [24]

Answer:

ok but this number is for school another one number soon tell you

6 0
3 years ago
Why is the atomic weight of carbon reported as 12.011 in the table of elements and the periodic table in the front inside cover
Oduvanchick [21]
The atomic weight reported in the periodic table of elements for Carbon is the average weight of all the known isotopes of Carbon occurring naturally. There are 3: Carbon-12, Carbon-13 and Carbon-14. The numbers represent the mass numbers, or the sum of neutrons and protons in the nucleus. Each of the individual masses are multiplied with their individual percentage abundances. Then, when you add them up, it will yield the average atomic weight equal to 12.011 amu or grams/mole C.
5 0
4 years ago
The gas OF2 can be produced from the electrolysis of an aqueous solution of KF, as shown in the equation below.
Readme [11.4K]

Answer:

A) 6.48 g of OF₂ at the anode.

Explanation:

The gas OF₂ can be obtained through the oxidation of F⁻ (inverse reaction of the reduction presented). The standard potential of the oxidation is the opposite of the standard potential of the reduction.

H₂O(l) + 2 F⁻(aq) → OF₂(g) + 2 H⁺(aq) + 4 e⁻    E° = -2.15 V

Oxidation takes place in the anode.

We can establish the following relations:

  • 1 Faraday is the charge corresponding to 1 mole of e⁻.
  • 1 mole of OF₂ is produced when 4 moles of e⁻ circulate.
  • The molar mass of OF₂ is 54.0 g/mol.

The mass of OF₂ produced when 0.480 F pass through an aqueous KF solution is:

0.480F.\frac{1mole^{-} }{1F} .\frac{1molOF_{2}}{4mole^{-} } .\frac{54.0gOF_{2}}{1molOF_{2}} =6.48gOF_{2}

7 0
3 years ago
Given the following unbalanced equation:
Lorico [155]
<h3>Answer:</h3>

8.01 mol MgO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Compounds

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + O₂ → MgO

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 8.01 moles Mg

[Solve] moles MgO

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg → 2 mol MgO

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                       \displaystyle 8.01 \ mol \ Mg(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 8.01 \ mol \ MgO
3 0
3 years ago
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