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ruslelena [56]
3 years ago
9

If you wanted to completely react 150 grams of FeBry, how many moles of sulfuric acid (H,SO) will you need to use?​

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

Sulfuric acid, spent appears as a black oily liquid. Corrosive to metals and tissue. Density 15 lb /gal.

Explanation:

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Virty [35]
When I answered i got D
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Solid aluminum metal and diatomic bromine liquid react spontaneously to form a solid product. give the balanced chemical equatio
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Aluminum has a chemical formula of Al, while diatomic bromine has a chemical formula of Br₂. The balanced chemical reaction is shown below:

<em>2 Al (s) + 3 Br₂ (l) → 2 AlBr₃ (s)</em>

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Think of a bath sponge. What happens when you squeeze it? How could you explain it from the point of view of the state of the ag
harkovskaia [24]

Answer:

What happens when it is squeezed is that its volume increases, the pressure of the material increases.

Explanation:

This is due to the fact that the elastic modulus of the sponge is high and withstands broad forces without deforming its structure, since the force is made within the proportional limit of its particles without modifying or permanently deforming them, that is why when stopping doing pressure or force on it its shape returns to being the original, this also happens due to the phenomenon of resilience

3 0
3 years ago
When 20.0 grams of an unknown compound are dissolved in 500. grams of benzene, the freezing point of the resulting solution is 3
Lelu [443]

Answer: 120g/mol

Explanation:

The first step we are to take is to calculate the freezing point depression of the solution.

ΔT(f) = freezing point of pure solvent - freezing point of solution

ΔT(f) = 5.48 - 3.77

ΔT(f) = 1.71°C

Next we are to calculate the molal concentration of the solution using freezing point depression

ΔT(f) = K(f) * m

m = ΔT(f)/K(f)

m = 1.71/5.12

m = 0.333 molal

Now, we calculate the molecular weight of the unknown...

m = 0.333 mol = 0.333 mol X per kg of benzene

moles of X = 0.333 mol of X per kg of benzene * 0.5kg of benzene

moles of X = 0.1665

molecular weight of X = 20g of X/0.1665

molecular weight of X = 120/mol

5 0
3 years ago
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