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Ipatiy [6.2K]
3 years ago
8

Water at a gauge pressure of 3.8 atm at street level flows into an office building at a speed of 0.68 m/s through a pipe 5.4 cm

in diameter. The pipe tapers down to 2.5 cm in diameter by the top floor, 18 m above, where the faucet has been left open. (Figure 1)Calculate the flow velocity in the pipe on the top floor. Assume no branch pipes and ignore viscosity.
v=________

Part b: Calculate the gauge pressure in the pipe on the top floor. Assume no branch pipes and ignore viscosity. Express your answer using two significant figures.
p=________
Physics
1 answer:
Nataliya [291]3 years ago
7 0
kxubj ysufuxtfuvhxub
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There is a 250-m-high cliff at half dome in yosemite national park in california. suppose a boulder breaks loose from the top of
lorasvet [3.4K]

Part A. For this part, we use two equations for linear motion:

<span>y = y0 + v0 t + 0.5 g t^2                   ---> 1</span>

<span>vf = v0 + g t                                         ---> 2</span>

First we solve for t using equation 1: y0 = 0 (initial point at top), y = 250 m, v0 = 0 (at rest)

250 = 0.5 (9.8) t^2

t = 7.143 s

Now we solve for final velocity vf using equation 2:

vf = g t

vf = 9.8 (7.143)

vf = 70 m/s

 

Part B. First we solve for the time it takes for the sound to reach the tourist.

t(sound) = 250 / 335 = 0.746 s

Therefore the total time would be:

t = 0.746 s + 0.300 s

t = 1.05 s

 

<span>Hence there is enough time for the tourist to get out before the boulder hits him.</span>

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4 years ago
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Hey if you talk to me i will mark you as a brainliest and if you answer all my question
Fittoniya [83]

Answer:

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Explanation:

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Mars, which has a radius of 3.4 × 106 m and a mass of 6.4 × 1023 kg, orbits the Sun, which has a mass of 2.0 × 1030 kg at a dist
Elena L [17]

Answer:

Tangential speed of Mass revolution is greater

Explanation:

In the above question, we are given the following values:

Radius of Mars = 3.4 × 10^6 m

Mass of Mars = 6.4 × 10^23 kg

Mass of the sun = 2.0 × 10^30 kg at a distance of 2.3 × 10^11m.

Mar’s revolution around the sun = 687 days.

Time of Revolution = 24 hours and 37 minutes to complete one revolution.

Step 1

Find the tangential speed of rotation of Mars

Rotation of Mars = 2 × π × r

Radius of Mars = 3.4 × 10^6 m

Rotation of Mars = 2 × π × 3.4 × 10^6 m

Rotation of Mars = 21362830.044m

= 21.4 × 10^6 m

Tangential Speed of rotation for Mars = Rotation of Mars/ time

Time = 24 hrs 37 minutes

Converting to seconds = 88620s

Tangential Speed of rotation = 21.4 × 10^6 m/ 88620s

= 241.48047845m/s

= 241.5 m/s

Step 2

revolution of Mars = 2 × π × d

d = 2.3 × 10^11m.

= 2 × π × 2.3 × 10^11m = 1.45 × 10^12m

Revolution of Mars = 687 days

Converting 687 days to seconds = 59356800s

Tangential Speed of Revolution of Mars = Revolution of Mars/ times

Tangential Speed of Revolution = 1.45 × 10^12m/595356800s

Tangential Speed of Revolution = 24420m/s

Comparing the Tangential Speed of Rotation with the Tangential speed of Revolution, we can see the GREATER ONE IS THE TANGENTIAL SPEED OF REVOLUTION.

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The property of matter that resists changes in motion is called...
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Answer:

inertia

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According to structural functionalists, what is government like in a mass society?
kvv77 [185]
The answer here is <span>The government is expansive</span>
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