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Ipatiy [6.2K]
3 years ago
8

Water at a gauge pressure of 3.8 atm at street level flows into an office building at a speed of 0.68 m/s through a pipe 5.4 cm

in diameter. The pipe tapers down to 2.5 cm in diameter by the top floor, 18 m above, where the faucet has been left open. (Figure 1)Calculate the flow velocity in the pipe on the top floor. Assume no branch pipes and ignore viscosity.
v=________

Part b: Calculate the gauge pressure in the pipe on the top floor. Assume no branch pipes and ignore viscosity. Express your answer using two significant figures.
p=________
Physics
1 answer:
Nataliya [291]3 years ago
7 0
kxubj ysufuxtfuvhxub
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D- Repulsion

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A 0.150 kg stone rests on a frictionless, horizontal surface. A bullet of mass 9.50 g, traveling horizontally at 380 m/s, strike
Anvisha [2.4K]

Answer:

(a)Magnitude=28.81 m/s

Direction=33.3 degree below the horizontal

(b) No, it is not perfectly elastic collision

Explanation:

We are given that

Mass of stone, M=0.150 kg

Mass of bullet, m=9.50 g=9.50\times 10^{3} kg

Initial speed of bullet, u=380 m/s

Initial speed of stone, U=0

Final speed of bullet, v=250m/s

a. We have to find the magnitude and direction of the velocity of the stone after it is struck.

Using conservation of momentum

mu+ MU=mv+ MV

Substitute the values

9.5\times 10^{-3}\times 380 i+0.150(0)=9.5\times 10^{-3} (250)j+0.150V

3.61i=2.375j+0.150V

3.61 i-2.375j=0.150V

V=\frac{1}{0.150}(3.61 i-2.375j)

V=24.07i-15.83j

Magnitude of velocity of stone

=\sqrt{(24.07)^2+(-15.83)^2}

|V|=28.81 m/s

Hence, the magnitude and direction of the velocity of the stone after it is struck, |V|=28.81 m/s

Direction

\theta=tan^{-1}(\frac{y}{x})

=tan^{-1}(\frac{-15.83}{24.07})

\theta=tan^{-1}(-0.657)

=33.3 degree below the horizontal

(b)

Initial kinetic energy

K_i=\frac{1}{2}mu^2+0=\frac{1}{2}(9.5\times 10^{-3})(380)^2

K_i=685.9 J

Final kinetic energy

K_f=\frac{1}{2}mv^2+\frac{1}{2}MV^2

=\frac{1}{2}(9.5\times 10^{-3})(250)^2+\frac{1}{2}(0.150)(28.81)^2

K_f=359.12 J

Initial kinetic energy is not equal to final kinetic energy. Hence, the collision is not perfectly elastic collision.

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3 years ago
In a series circuit, when batteries are added to the circuit the voltage will _____ and the current will _____.
Eva8 [605]

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For a moon orbiting its planet, rp is the shortest distance between the moon and its planet andra is the longest distance betwee
Natasha2012 [34]

Answer: D. 0.57

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Then:

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e=\frac{0.73 r_{a}}{1.27 r_{a}}

e=0.57 This is the moon's orbital eccentricity

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3 years ago
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