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1 year ago

The volume in the pump when the pump piston is all the way down represents the _______

Physics

1 answer:

sveticcg [70]1 year ago

7 0

The volume in the pump when the pump piston is all the way down represents the end systolic volume.

<h3>What is systolic volume?</h3>

End systolic volume is the volume of blood in a ventricle at the end of contraction, or systole, and the beginning of filling, or diastole.

End systolic volume is the lowest volume of blood in the ventricle at any point in the cardiac cycle.

Thus, the volume in the pump when the pump piston is all the way down represents the end systolic volume.

Learn more about volume here: brainly.com/question/1972490

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This. please help me.

kramer

The transfer of heat from the Sun is in the form of thermal radiation (also called infrared radiation)
The transfer of heat at the person’s feet is by thermal conduction. During the day the sand will be hot so if you step on it with bare feet there will be conduction of heat to the feet.

3 0

2 years ago

Before beginning a long trip on a hot day, a driver inflates anautomobile tire to a gauge pressure of 2.70 atm at 300 K. At the

anygoal [31]

Answer:

The value is the temperature of the air inside the tire $T_{2} =$ 340.54 K

% of the original mass of air in the tire should be released 99.706 %

Explanation:

Initial gauge pressure = 2.7 atm

Absolute pressure at inlet $P_{1}$ = 2.7 + 1 = 3.7 atm

Absolute pressure at outlet $P_{2}$ = 3.2 + 1 = 4.2 atm

Temperature at inlet $T_{1}$ = 300 K

(a) Volume of the system is constant so pressure is directly proportional to the temperature.

$\frac{T_{2} }{T_{1} } = \frac{P_{2} }{P_{1} }$

$\frac{T_{2} }{300} = \frac{4.2}{3.7}$

$T_{2} =$ 340.54 K

This is the value is the temperature of the air inside the tire

(b). Since volume of the tyre is constant & pressure reaches the original value.

From ideal gas equation P V = m R T

Since P , V & R is constant. So

m T = constant

$m_{1} T_{1} = m_{2} T_{2}$

$\frac{m_{2} }{m_{1} } = \frac{T_{1} }{T_{2} }$

$\frac{m_{2} }{m_{1} } = \frac{300}{354.54}$

$\frac{m_{2} }{m_{1} } =0.00294$

value of the original mass of air in the tire should be released is $\frac{m_{2} - m_{1}}{m_{1}}$

$\frac{0.00294-1}{1}$

⇒ -0.99706

% of the original mass of air in the tire should be released 99.706 %.

8 0

2 years ago

If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in th

Vladimir [108]

vector a = 3i - 2j - k and vector b = i + 4j + k, the unit vector, n, normal to the plane is (7i - j + 7k)/3√11

What is a vector?

A vector is a quantity having direction as well as magnitude.

Vectors can especially be used in determining the position of one point in space relative to another.

From the question,

The normal vector to the plane is c = a × b

we have that, a = 3i - 2j - k and b = i + 4j + k,

c = a × b

c = (3i - 2j - k) × (i + 4j + k)

= 3i × i + (- 2j) × i + (-k) × i + 3i × 4j + (- 2j) × 4j + (-k) × 4j + 3i × k + (- 2j) × k + (-k) × k

= 3i × i - 2j × i - k × i + 12i × j - 8j × j - 4k × 4j + 3i × k - 2j × k - k × k

It is known that

i × i = 0,

j × j = 0 and

k × k = 0.

we also have that

c = 3(0) - 2(-k) - (-j) + 12k - 8(0) - 16(-i) + 3(-j) - 2i - 0

c = 0 + 2k + j + 12k - 0 + 16i - 3j - 2i

c = 16i - 2i + j - 3j + 2k + 12k

c = 14i -2j + 14k

The unit vector normal to the plane n = c/ |c|

where |c| is the magnitude of c

= √(14² + (-2)² + 14²) = √(196 + 4 + 196)

= √396

= √(36 × 11)

= 6√11

we can write that n = c/|c|

= (14i -2j + 14k)/6√11

we simplify further

= 2(7i - j + 7k)/6√11

= (7i - j + 7k)/3√11

So, the unit vector normal to the plane is (7i - j + 7k)/3√11

Learn more about vectors at: brainly.com/question/25705666

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7 0

1 year ago

What happens when the clapper of an electric doorbell move to strike the bell?

faust18 [17]

Answer: The clapper of an electric doorbell is an electromagnet. When the clapper of a doorbell strikes the bell, it opens an electric circuit. The electromagnet of an electric motor is connected to a permanent magnet. Only the shaft of an electric motor turns when current flows through the motor.

Explanation: hope this helped

5 0

2 years ago

Una mujer esta segando su prado con segadora eléctrica cuya cuchilla gira a 1500rpm. La mujer encuentra una zona de hierba alta

maks197457 [2]

Answer:

α= 15.4[rad/s^2], 500 [rev/min]

Explanation:

La aceleración angular constante esta definida por la siguiente ecuación:

$w=w_{0} + \alpha *t\\Donde:\\w=2000 [\frac{rev}{min}]*[\frac{1min}{60s} ] *[\frac{2\pi rad}{1 rev} ]=209.4[\frac{rad}{s} ]\\w_{0} =1500 [\frac{rev}{min}]*[\frac{1min}{60s} ] *[\frac{2\pi rad}{1 rev} ]=157.1[\frac{rad}{s} ]\\t=3.4[s]\\reemplazando:\\209.4-157.1=\alpha *(3.4)\\\\alpha =15.4[\frac{rad}{s^{2} } ]$

Para poder llegar a las 2000 [revoluciones /min] estando en 1500 [rev/min], la cuchilla tuvo que incrementar su numero de revoluciones a 500 [rev/min]. Mientras aceleraba.

3 0

2 years ago