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PilotLPTM [1.2K]
3 years ago
10

What would Hubble's constant be if we found one galaxy moving away at 30,000 km/s at a distance of 600 Mpc?

Physics
1 answer:
lora16 [44]3 years ago
3 0

Answer:

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

Explanation:

The Hubble's Constant can be found by the following formula:

v = H_o D\\\\H_o = \frac{v}{D}

where,

H₀ = Hubble's Constant = ?

v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s

D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)

D = 18.52 x 10²⁴ m

Therefore,

H_o = \frac{3\ x\ 10^7\ m/s}{18.52\ x\ 10^{24}\ m}

<u>H₀ = 1.6 x 10⁻¹⁸ s⁻¹</u>

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Answer:

Artificial is the BEST synonym for synthetic

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3 years ago
A new record for running the stairs of the Empire State Building were set on February 4, 2003. The 86 flights, with a total of 1
Roman55 [17]

Answer:

Power = 377.35 W or Power = 0.5065 hp

Explanation:

Given:

Number of steps, n = 1576

height of each step, h = 0.20 m

Total height achieved, H = nh = 1576 × 0.20 = 315.2 m

Mass of the runner, M = 70.0 kg

Total time taken, t = 9 minutes 33 seconds = (9 × 60) + 33 = 573 seconds

Now, the potential energy gained by the runner,

E = MgH

where, g is the acceleration due to the gravity

on substituting the values in the above formula, we get

E = 70 × 9.8 × 315.2

or

E = 216227.2 J

also,

Energy = Power × time

therefore,

Power = Energy/time

or

Power = 216227.2 J / 573

or

Power = 377.35 W

Now,

745 watt = 1 hp

or

1 watt = 1/745 hp

thus,

Power = 377.35 W = 337.35 × (1/745) hp

or

Power = 0.5065 hp

4 0
3 years ago
Which form of energy is responsible for the change of state here?
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Answer:

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An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally
amid [387]

The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

v^{2} - u^{2} = 2as

0 - 12^2 = 2*a*42

a = - 144 / 84

a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

Learn more about tension here:

<u>brainly.com/question/13772148</u>

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2 years ago
If you measured the mass of a book to be 2.5 kilograms how many grams is that
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