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gayaneshka [121]
3 years ago
10

Which statements below are true? Check all that apply. A. If motion starts and stops at the same location, then the displacement

is zero. B. Distance measurements must include magnitude, unit, and direction. I c. Distance is always greater than or equal to the magnitude of the displacement D. Displacement can be fully described with a magnitude and a unit.​
Physics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

A. If motion starts and stop at the same location, then the displacement is zero

C. Distance is always greater than or equal to the magnitude of the displacement

Explanation:

The displacement of a body is a vector quantity that gives the shortest (straight line) distance moved by an object in motion, from its initial position to its final position. The displacement can also be described as the final position relative to the initial position of an object, such that the displacement vector, 's', is given as follows;

s = x_f - x _i

The displacement gives the direct length between two points, with regards to the direction of motion between the points. It can only be described by both the magnitude and the direction

Therefore, displacement can be positive (forward motion), negative (backward motion), or zero (where there is motion that stops at the starting point)

Therefore, a correct options is; <em>If motion starts and stop at the same location, then the displacement is zero</em>

<em />

Displacement, being a vector quantity will have both magnitude and direction

Distance, however, is a scalar quantity, it specifies only magnitude, but does not specify direction

Distance, describes the length of the path taken from one point to the other. Distance gives the total movement a body makes, without regards to the direction of the motion

Therefore, distance is always positive or zero (here only the object is stationary)

Therefore, a correct option is; <em>Distance is always greater than or equal to the magnitude of the displacement</em>

Therefore, the correct options are;

If motion starts and stop at the same location, then the displacement is zero

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Irina-Kira [14]

Answer:

x=?

dt=?

vi=23m/s

vf=0m/s (it stops)

d=0.25m/s^2

time =

vf=vi+d: 0=23m/s+(0.25m/s^2)t

t=92s

displacement=

vf^2=vi^2+2a(dx)

23^2=0^2+2(0.25m/s^2)x =-1058m

Explanation:

you can find time from vf = vi + a(Dt): 0 = 23 m/s + (0.25 m/s/s)t so t = 92 s and you can find the displacement from vf2 = vi2 + 2a(Dx) and find the answer in one step: 232 = 02 + 2(0.25 m/s/s)x so x = -1058 m

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3 years ago
It is warmer near the equator because that is where the Earth gets the most direct sunlight. T or f
Anni [7]
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Read 2 more answers
Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp
shutvik [7]

Answer: 500 Watts

Explanation:

Power P is the speed with which work W is done. Its unit is Watts (W), being 1 W=\frac{1 Joule}{1 s}.

Power is mathematically expressed as:

P=\frac{W}{t} (1)

Where t is the time during which work W  is performed.

On the other hand, the Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (1J=(1N)(1m)=Nm  ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (2)

In this case, we have the following data:

F=500 N

d=10 m

t=10 s

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

W=(500 N)(10 m) (3)

W=5000 J (4)

Substituting (4) in (1):

P=\frac{5000 J}{10 s} (5)

Finally:

P=500 W

3 0
3 years ago
A 250 g block of ice is removed from the refrigerator at -8.0°C. How much thermal energy does the ice absorb as it warms to room
zlopas [31]

Answer:

Q = 114895 J

Explanation:

To find the thermal energy gained by the ice you use the following formula:

Q=mc(T_2-T_1)+H_f\ m

m: mass of the ice = 0.250kg

T2: final temperature = 22°C

T1: initial temperature = -8.0°C

Hf: heat of fusion of water = 3.34*10^5 J/kg

c: specific heat of water = 4186 J/kg

By replacing the values of the parameters you have:

Q=(0.250kg)(4186J/kg\°C)(22+8)\°C+(3.34*10^5 J/kg)(0.250kg)\\\\Q=114895\ J

where you have considered that ice melts completely

3 0
3 years ago
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MA_775_DIABLO [31]

Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:

(1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s) = ((1250 + 448) kg) <em>v</em>

where <em>v</em> is the velocity of the system. Solve for <em>v</em> :

<em>v</em> = ((1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s)) / (1698 kg)

<em>v</em> ≈ (30.3 <em>i</em> + 12.0 <em>j</em> ) m/s

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2 years ago
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