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lesya692 [45]
3 years ago
11

Iron(II) carbonate (FeCO3) has a solubility product constant of 3.13 x 10-11 . Calculate the molar solubility of FeCO3 in water

Physics
1 answer:
fomenos3 years ago
7 0
<span>The molar solubility of a substance is the number of moles that dissolve per liter of solution.  The dissociation equation FeCO3 in water would be as follows:

</span><span>FeCO3 → Fe2+ + CO3 2-
</span>
We calculate as follows:

Ksp = [Fe2+][CO3 2-] 

<span>Let X = [Fe2+] - then X = [CO3 2-] 
</span>
<span>Ksp = X² </span>
<span>(3.13*10^-11) = X² </span>
<span>X = √( 3.13*10^-11) </span>
<span>X = 5.59*10^-6 M
</span>
Hope this answers the question. Have a nice day.
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The centripetal acceleration is given by

    a = v² / r

For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship

    v = d / t

The distance traveled Esla orbits, in a circle the distance is

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Time in time to complete the orbit, called period

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Let's replace

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    G M / r² = (2π r / T)² / r

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Let's reduce the magnitudes to the SI system

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      r = 0.3787 10¹² m

      r = 3.787 10¹¹ m

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