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lesya692 [45]
2 years ago
11

Iron(II) carbonate (FeCO3) has a solubility product constant of 3.13 x 10-11 . Calculate the molar solubility of FeCO3 in water

Physics
1 answer:
fomenos2 years ago
7 0
<span>The molar solubility of a substance is the number of moles that dissolve per liter of solution.  The dissociation equation FeCO3 in water would be as follows:

</span><span>FeCO3 → Fe2+ + CO3 2-
</span>
We calculate as follows:

Ksp = [Fe2+][CO3 2-] 

<span>Let X = [Fe2+] - then X = [CO3 2-] 
</span>
<span>Ksp = X² </span>
<span>(3.13*10^-11) = X² </span>
<span>X = √( 3.13*10^-11) </span>
<span>X = 5.59*10^-6 M
</span>
Hope this answers the question. Have a nice day.
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g The electric power needs of a community are to be met by windmills with 40-m-diameter rotors. The windmills are to be located
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Answer:

Explanation:

Given Data

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Expression to calculate the exergy of the air is

E = V ² / 2

Substitute the value in above expression

E = ( 6 m / s ) ² / 2

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Expression to calculate the density of the air is

P v =m R T

m /v = P  /RT ⋯ ⋯( I )

Here  

m  is the mass of the air,  

v  is the volume of the air,  

P  is the atmospheric pressure,  

T  is the standard temperature at the atmospheric pressure and  

R  is the gas constant

As the density is

ρ = m /V

Substitute the value in expression (I)

ρ = 101  kP a /( 0.287 k J / k g ⋅ K ) ( 298 K )

ρ = 1.180 k g / m ²

Expression to calculate the mass flow rate is

m = ρ A V ⋯ ⋯ ( I I )

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Expression to calculate the  A  is

A = π /4  d ²

Substitute the value in above expression

A = π /4 ( 40 m ²)

A = 1256.63 m ²

Substitute the value in expression (II)

m = ( 1.180 k g / m ³) ( 1256.63 m ²) ( 6 m / s )

m = 8896.94  k g / s

Expression to calculate the maximum power available to the windmill is

P w = m ( V ² /2 )

Substitute the value in above expression

P w = 8896.94  k g / s ( (6m/s)²/2 )

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n = P o /P w

Substitute the value in above expression

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