Answer:
How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice cube? = 6.02 kJ/mol
A. 108 kJ
B. 102 kJ
C. 5.64 kJ
D. 936 kJ
E. none of the above
<em>5.64 kJ</em>
Explanation:
The Heat of fusion is the heat energy required to dissolve a given mass of ice at melting point.
<h3>
Step by Step Calculation</h3>
The heat energy required to dissolve ice can be calculated using the expression below;
Q = ΔH
x m ...............................................1
where Q is the heat energy required;
ΔH
is the heat of fusion for ice;
m is the mole
All the parameters above are provided in the question except m, so to get m we use the molar mass of water (also for ice) which is 18.01528 g/mol
.
<em>This means that 18.01528 g of ice is contained in one mole, therefore the mole for 16.87 g of ice is given as;</em>

m = 0.9364 mole of ices
Now the parameters are complete, we are given;
ΔH
= 6.02 kJ/mol
m = 0.9364 mol
Q =?
Substituting into equation 1, we have
Q = 6.02 kJ/mol x 0.9364 mol
Q = 5.64 kJ
<em>Therefore, the energy required to melt 16.87 g of ice is 5.64 kJ</em>
Answer: I think cars are designed to have crumble zone because lets say you're going 60-70 mph and you hit a brick wall that cant move, it would be a very hard jolt causing the beings inside to get thrown forward, but if it has a crumble zone it would slow the the jolt from is slowing down in the hit.
The "i" component of a vector is in the x-direction. Therefore, the x-component is 3 m/s.
Answer:
1: surface temperature
2: red giant
3: The brightest stars are called supergiants. Star clusters are rich in stars just off the main sequence called red giants. Main sequence stars are called dwarfs.
4: A white dwarf is very dense
5: red giant
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For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km