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3 years ago

11

Iron(II) carbonate (FeCO3) has a solubility product constant of 3.13 x 10-11 . Calculate the molar solubility of FeCO3 in water

1 answer:

fomenos3 years ago

7 0

<span>The molar solubility of a substance is the number of moles that dissolve per liter of solution. The dissociation equation FeCO3 in water would be as follows:

</span><span>FeCO3 → Fe2+ + CO3 2-
</span>
We calculate as follows:

Ksp = [Fe2+][CO3 2-]

<span>Let X = [Fe2+] - then X = [CO3 2-]
</span>
<span>Ksp = X² </span>
<span>(3.13*10^-11) = X² </span>
<span>X = √( 3.13*10^-11) </span>
<span>X = 5.59*10^-6 M
</span>
Hope this answers the question. Have a nice day.

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