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lesya692 [45]
3 years ago
11

Iron(II) carbonate (FeCO3) has a solubility product constant of 3.13 x 10-11 . Calculate the molar solubility of FeCO3 in water

Physics
1 answer:
fomenos3 years ago
7 0
<span>The molar solubility of a substance is the number of moles that dissolve per liter of solution.  The dissociation equation FeCO3 in water would be as follows:

</span><span>FeCO3 → Fe2+ + CO3 2-
</span>
We calculate as follows:

Ksp = [Fe2+][CO3 2-] 

<span>Let X = [Fe2+] - then X = [CO3 2-] 
</span>
<span>Ksp = X² </span>
<span>(3.13*10^-11) = X² </span>
<span>X = √( 3.13*10^-11) </span>
<span>X = 5.59*10^-6 M
</span>
Hope this answers the question. Have a nice day.
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As long as no water can escape, the mass of the ice before melting must equal the mass of the liquid water after.

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3 years ago
The potential energy of a 1.7 x 10-3 kg particle is described by U (x )space equals space minus (17 space J )space cos open squa
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Answer:

Explanation:

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M = 1.7 × 10^-3 kg

Given a potential as a function of x

U(x) = -17 J Cos[x/0.35 m]

U(x) = -17 Cos(x/0.35)

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Let find the force at x = 0

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F = -17 × -Sin(x/0.35) / 0.35

F = 48.57 Sin(x/0.35)

At x = 0

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Then,

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Then,

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This shows that k = 0

Then, angular frequency can be calculated using

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So, since k = 0 at x = 0

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3 years ago
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Crank

Answer:

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