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snow_tiger [21]
3 years ago
15

Question 7 (2 points)

Physics
1 answer:
DiKsa [7]3 years ago
6 0
This has to do with independent and dependent variables. The independent variable is what affects the dependant variable, so the question is, does a students mark on a test affect their hours of sleep or does their hours of sleep affect their test results? Which one makes more sense? I would say the latter.
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A kid moving 3.18 m/s jumps on a slip and slide(Uk=0.0751). How far has he slid when his velocity is reduced to 2.00 m/s?
STALIN [3.7K]
F=ma (Newton's second law of motion).

Then,
a = F/m = Uk*mg/m = Uk*g = 0.0751*9.81 = 0.737 m/s^2 (should be negative since a deceleration is expected).

v = Sqrt (u^2-2ad), Where v = final velocity, u=initial velocity, a = acceleration, d = distance moved.

Therefore,

v^2-u^2 = -2ad => d = (v^2-u^2)/-2a = (2^2-3.18^2)/-2*0.737 = 4.15 m
7 0
4 years ago
Can someone please help me ASAP???!!!
olganol [36]

Answer: The answers are:

Explanation:

1. C

2. A

3. C

4. B

5. D

8 0
2 years ago
Need Help ASAP!!<br> (Picture)
olchik [2.2K]

Answer:225000000000

Explanation:

5 0
3 years ago
A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of
aliina [53]

Answer:

Centripetal acceleration = 1.46m/s²

Explanation:

Given r = radius = 50m

v = distance/time = 200m/23.4s = 8.55m/s

Acceleration = v²/r = 8.55²/50 = 1.46m/s²

4 0
3 years ago
Read 2 more answers
522 J of work are done on a system in a process that decreases the system's thermal energy by 240 J. How much heat energy is tra
ELEN [110]

Answer:

ΔQ = - 762 J (Negative Sign shows heat transfer from the system)

Explanation:

The heat transferred to or from the system can be given by using First law of Thermodynamics as follows:

\Delta Q = \Delta U + W

where,

ΔQ = Heat Transferred to or from system = ?

ΔU = Change in Internal Energy of System = Change in Thermal Energy

ΔU = - 240 J (negative sign due to decrease in energy)

W = Work done on system = -522 J (negative sign due to work done "on" system)

Therefore,

\Delta Q = - 240 J - 522 J

<u>ΔQ = - 762 J (Negative Sign shows heat transfer from the system)</u>

7 0
3 years ago
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