Answer:
D) the second at the doorknob
Explanation:
The torque exerted by a force is given by:
where
F is the magnitude of the force
d is the distance between the point of application of the force and the centre of rotation
is the angle between the direction of the force and d
In this problem, we have:
- Two forces of equal magnitude F
- Both forces are perpendicular to the door, so
- The first force is exerted at the midpoint of the door, while the 2nd force is applied at the doorknob. This means that d is the larger for the 2nd force
--> therefore, the 2nd force exerts a greater torque
Answer:
E = 0.437 N/C
Explanation:
Given that,
Charge,
Electric force,
Let the strength of the electric field is E. We know that, the electric force is given by :
F = qE
Where
E is the electric field strength
So, the strength of the electric field is equal to 0.437 N/C.
Answer:60 rev/min
Explanation:
Given
angular speed of first shaft
Moment of inertia of second shaft is seven times times the rotational speed of the first i.e. If I is the moment of inertia of first wheel so moment of inertia of second is 7 I
As there is no external torque therefore angular momentum is conserved
Answer:
The punnet chart indicate the cross between a black cat and a spotted cat.
Explanation:
As the punnet chart was not given with the question, the question is searched and found online which is as attached herewith.
As seen from the punned table the column head has two capital H which indicate that the cat is a black cat.
White the row heads indicate a Capital and a small h thus this is a spotted cat
Thus the punnet chart indicate the cross between a black cat and a spotted cat.
