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xz_007 [3.2K]
3 years ago
12

How many grams of ethanol c2h5oh can be made by the fermentation of 1150 g of glucose?

Chemistry
1 answer:
ozzi3 years ago
5 0
Answer is: 588.15 <span>grams of ethanol.
</span>Chemical reaction: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂.
m(C₆H₁₂O₆) = 1150 g.
n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 1150 g ÷ 180.16 g/mol.
n(C₆H₁₂O₆) = 6.38 mol.
From chemical reaction: n(C₆H₁₂O₆) : n(C₂H₅OH) = 1 : 2.
n(C₂H₅OH) = 12.76 mol.
m(C₂H₅OH) = 12.76 mol · 46.07 g/mol.
m(C₂H₅OH) = 588.15 g.
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Name the element described in each of the following:
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Alkaline earth metal whose cation isoelectric with Kr is strontium (Sr).

What is Alkaline earth metal?

Six chemical elements from group 2 of the periodic chart make up the alkaline earth metals. They are boron (R), barium (Ba), calcium (Ca), strontium (Sr), magnesium (Mg), beryllium (Be), and radium (Ra). The elements share many characteristics, including being glossy, silvery-white, moderately reactive metals at standard pressure and temperature.

They share a full outer s-orbital structurally, meaning that this orbital includes all two of its electrons, which the alkaline earth metals rapidly lose to form cations with a charge of +2 and an oxidation state of +2.

All of the identified alkaline earth metals are found in nature, albeit radium is not a primordial element but only appears as part of the decay chain of uranium and thorium.

The chemical element strontium has the atomic number 38 and the symbol Sr. Strontium is a soft, silver-white, yellowish metallic element that is an alkaline earth metal and has a strong reactivity to chemicals. When the metal is exposed to air, a thick layer of dark oxide forms. Similar to its two vertical neighbors in the periodic table, barium and calcium, strontium exhibits physical and chemical characteristics. It is mostly obtained from the minerals celestine and strontianite, where it is found naturally.

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8 0
2 years ago
determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass
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The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

K_{f}or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             ΔT_{f} = i ×K_{f} ×m

T⁰-T_{s}  = i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water     in     kg}

in which,

ΔT_{f} = change in freezing point

ΔT_{s} = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T_{s} = 1 ×1.86°C/m ×\frac{30.7}{92.09g/mol * 0.376kg}

T_{s} = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

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Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

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