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exis [7]
3 years ago
11

PLEASE HELP ME !!!!

Chemistry
1 answer:
labwork [276]3 years ago
3 0

Answer:

electrons..............

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Give the formula of each coordination compound. Include square brackets around the coordination complex. Do not include the oxid
kogti [31]

Answer:

a) K2[Ni(CN)4]

b) Na3[Ru(NH3)2(CO3)2]

c) Pt(NH3)2Cl2

Explanation:

Coordination compounds are named in accordance with IUPAC nomenclature.

According to this nomenclature, negative ligands end with the suffix ''ato'' while neutral ligands have no special ending.

The ions written outside the coordination sphere are counter ions. Given the names of the coordination compounds as written in the question, their formulas are provided above.

8 0
3 years ago
What do you know about Relative Dating
gizmo_the_mogwai [7]
<span>it tells you the sequence in which events occurred, not how long ago they occurred.</span>
8 0
3 years ago
Why does it seem to us as if rocks remain the same and don't change
qaws [65]
Most rocks that we encounter in our normal everyday lives are sedimentary rocks.  Sedimentary rocks are rocks that have been worn down gradually over long periods of time.  Because it takes very long periods of time (couple decades) for these rocks to change, it often seems as if they don't change at all, when in reality the change is too small for us to realize it!
3 0
2 years ago
What happens when an electron jumps energy from energy level 3 energy level 6 in an atom
Alik [6]

Explanation:

high energy to Low energy

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4 0
1 year ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Alinara [238K]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
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