H₂ (g) + F₂ (g) ⇌ 2 HF (g)
Sodium hydroxide +HCI ➙ sodium chloride +H2O Is this a:
1 answer:
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<h3>Answer:</h3>
25.4 g CH₄
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right<u> </u>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
1.58 mol CH₄
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of C - 12.01 g/mol
[PT] Molar Mass of H - 1.01 g/mol
Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
25.359 g CH₄ ≈ 25.4 g CH₄
The molecule with same molecular formula but different arrangement of atoms is said to be an isomer.
When 2,2-dimethylbutane reacts with chlorine in the presence of light gives three isomers that is (3-chloro-2,2-dimethylbutane),
(1-chloro-2,2-dimethylbutane) and
(1-chloro-3,3-dimethylbutane).
In above case, the molecular formula of all isomers are same i.e. but chlorine is arranged in different positions of carbon. Thus, results isomers.
The reaction is shown in the image.
