What might be a possible outcome if you left a soda in a glass bottle in the freezer for a very long time?

Scientists have categorized trees based on whether they keep or lose their leaves each year. Another logical way to categorize t

Zolol [24]

Answer:

D

Explanation:

I think but it is an better attempt than the other guy answer.

5 0

2 years ago

Which property describes a mixture? It cannot be separated by physical methods. It has a single chemical composition. It cannot

natima [27]

Answer:

it cannot be separated by physical methods

Explanation:

7 0

2 years ago

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1. Some athletes have as little as 3.0% body fat. If such a person has a body mass of 65 kg, how many pounds of body fat does th

77julia77 [94]

1. 3.0% ----> 3.0 kg fat= 100 kg body weigh
also remember that 1 kg= 2.20 lbs

$65 kg \frac{3.0 kg}{100 kg} x \frac{2.20 lb}{1 kg} = 4.29 lbs$

2. 0.94 g/mL----> 0.94 grams= 1 mL
1 Liters= 1000 mL
1kg= 1000 grams

$3 Liters \frac{1000 mL}{1 L} x \frac{0.94 grams}{1 mL} x \frac{1 kg}{1000 g} x \frac{2.20 lbs}{1 kg} = 6.20 lbs$

3 0

2 years ago

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How many moles of a gas sample are in a 10.0 L container at 373 K and 203 kPa? the gas constant is 8.31 L -kPa/ mol-K.

Zepler [3.9K]

I believe the answer is 0.33

5 0

2 years ago

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A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3

IRINA_888 [86]

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

$\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}$

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram