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liq [111]
3 years ago
15

Wave Properties

Chemistry
2 answers:
Aliun [14]3 years ago
8 0

Answer:

flutters per second is 80 and the period is 0.013.

Explanation:

i just took the test.

konstantin123 [22]3 years ago
3 0

Answer:

f = 80  flutter/ second

T= 0.0125 sec

Explanation:

Given data:

Fluttering of wings = 4800 time per minute

Frequency of wings = ?

Period for one wing in sec = ?

Solution:

There are 60 seconds in one minute, thus frequency of wings

4800/60 = 80  flutter per second

Period:

T = 1/f

T = 1/80

T= 0.0125 sec

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A gas occupies a volume of 202 ml at a pressure of 505 torr. To what pressure must the gas be subject in order to change the vol
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Answer:

1569 torr

Explanation:

Assuming ideal behaviour and constant temperature, we can solve this problem by using <em>Boyle's law</em>, which states:

  • V₁P₁ = V₂P₂

Where in this case:

  • V₁ = 202 mL
  • P₁ = 505 torr
  • V₂ = 65.0 mL
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We <u>input the data given by the problem</u>:

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a sealed container filled with argon gas at 35 c has a pressure of 832 torr. if the volume of the container is decreased by a fa
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Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

Where:

V₁ = Initial volume

V₂ = Final volume = V₁/2

P₁ = Initial pressure = 832 torr

P₂ = Final pressure  = Required

From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

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6 0
3 years ago
Read 2 more answers
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