pH of 0.40M triethylammonium chloride is 5.90.
<h3>What is pH?</h3>
A solution's acidity may be determined by looking at its pH, which is a measurement of hydrogen ion concentration. Pure water slightly separates into ions with roughly equal amounts of hydrogen and hydroxyl (OH) ions. [H+] is 107 for a neutral solution, or pH = 7.
<h3>Given : </h3>
Concentration of triethylammonium chloride = 0.40M
pH = ?
<h3>Solution: </h3>
(CH3CH2)3NHCl ------> (CH3CH2)3NH⁺ + Cl⁻
(CH3CH2)3NH⁺ will react with water to give H3O⁺ .
(CH3CH2)3N will have a Kb = 5.2 x 10 ^(-4)
Kw = Kb x Ka
=> Ka = Kw / Kb = 10^(-14) / 5.2 x 10 ^(-4)
=> Ka = 1.92 x 10^(-11)
so by the reaction we have ,
Ka = x²/(0.40 - x)
=> x = 1.2393 x 10 ^(-6)
now, pH = -log( [H3O⁺]) = - log ( 1.2393 x 10 ^(-6)) = 5.906
To learn more about pH :
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The balanced chemical equation of the reactions given is as follows:
- 2LiHCO3 -----> Li2CO3 + H2O + CO2
- 2 N2 + 5 O2 -----> 2 N2O5
- MgBr2 + KOH -----> KBr + Mg(OH)2
- Mn + 2 CuCl -----> 2 Cu + MnCl2
- 8 Zn + S8 -----> 8 ZnS
- 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
- 2 K + 2 H2O -----> 2 KOH + H2
- C5H12 + 8 O2 -----> 6H2O + 5 CO2
- 2 KOH + H2CO3 -----> 2 H2O + K2CO3
- C4H802 + 6 O2 -----> 4 H20 + 4 CO2
- 16 Al + 3 S8 ---> 8 Al2S3
<h3>How to balance chemical equations</h3>
Balancing of chemical equations is the process of adding numerical coefficients in front of moles of reactants and products to ensure that the moles of atoms of elements of the reactants is equal to the moles of atoms of products formed.
The balanced chemical equation of the reactions given is as follows:
- 2LiHCO3 -----> Li2CO3 + H2O + CO2
- 2 N2 + 5 O2 -----> 2 N2O5
- MgBr2 + KOH -----> KBr + Mg(OH)2
- Mn + 2 CuCl -----> 2 Cu + MnCl2
- 8 Zn + S8 -----> 8 ZnS
- 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
- 2 K + 2 H2O -----> 2 KOH + H2
- C5H12 + 8 O2 -----> 6H2O + 5 CO2
- 2 KOH + H2CO3 -----> 2 H2O + K2CO3
- C4H802 + 6 O2 -----> 4 H20 + 4 CO2
- 16 Al + 3 S8 ---> 8 Al2S3
Learn more about balancing of chemical equations at: brainly.com/question/15428811
Answer:
carbon group
All the carbon group atoms, having four valence electrons, form covalent bonds with nonmetal atoms; carbon and silicon cannot lose or gain electrons to form free ions, whereas germanium, tin, and lead do form metallic ions but only with two positive charges.
For this problem, we use the formula for radioactive decay which is expressed as follows:
An = Aoe^-kt
where An is the amount left after time t, Ao is the initial amount and k is a constant.
We calculate as follows:
An = Aoe^-kt
0.5 = e^-k(5730)
k = 1.21x10^-4
An = Aoe^-kt
An = 200e^-1.21x10^-4(17190)
An = 25
Therefore, about 175g is produced.