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QveST [7]
3 years ago
11

10. You are given 480 grams of the substance. It's molecular weight is 1440 g. How many

Chemistry
1 answer:
Mademuasel [1]3 years ago
6 0

Answer:

3

Explanation:

You might be interested in
Si se tiene 1mol de NO . cuantas moleculas de NO hay
kumpel [21]

if you have 1mol of NO. how many molecules of NO are there

Answer:

6.02 x 10²³ molecules

Explanation:

Given parameters:

Number of moles of NO = 1 mole

Unknown:

Number of molecules in NO;

Solution:

A mole of compound contains the Avogadro's number of particles.

  1 mole of a substance contains 6.02 x 10²³ molecules

So, 1 mole of NO contained 6.02 x 10²³ molecules

3 0
2 years ago
Lead has a density of 11.3 g/mL. If you have 105 grams of lead,
Elza [17]

Answer:

<h2>Volume = 9.29 mL</h2>

Explanation:

Density of a substance can be found by using the formula

Density( \rho) =  \frac{mass}{volume}

From the question

Density = 11.3 g/mL

mass = 105 g

Substitute the values into the above formula and solve for the volume

That's

11.3 =  \frac{105}{v}

Cross multiply

11.3v = 105

Divide both sides by 11.3

v =  \frac{105}{11.3}

v = 9.29203

We have the final answer as

<h3>Volume = 9.29 mL</h3>

Hope this helps you

6 0
3 years ago
The following exothermic reaction is allowed to reach equilibrium. What
Anon25 [30]
The answer is gonna be the last one :)
5 0
2 years ago
The rate constant for a certain reaction is measured at two different temperatures:
Talja [164]

Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]

k_1 = rate constant at temperature T_1 = 2.3\times 10^8

k_2 = rate constant at temperature T_2 = 4.8\times 10^8

E_a= activation energy = ?

R= gas constant = 8.314 J/kmol

T_1 = temperature = 280.0^0C=(273+280)=553K

T_2 = temperature = 376.0^0C=(273+376)=649K

Putting in the values ::

ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]

E_a=22689.8J/mol

The activation energy Ea for this reaction is 22689.8 J/mol

3 0
3 years ago
Can U help me fill in the blank pls !!
KonstantinChe [14]

Answer:

Molecules, arranged, cube

Explanation:

These are possible answers.

5 0
3 years ago
Read 2 more answers
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