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3 years ago

How does 6+(-3) equal 3? I don't understand what I have to do to get that answer.

Mathematics

2 answers:

WITCHER [35]3 years ago

8 0

Answer:

look at the explanantion <33

Step-by-step explanation:

so negative numbers are basically numbers with minus signs in front of them. So when you add a negative number, its basically like subtracting a number. so by adding negative three, youre subtacting 3.

6-3 is 3. does that make sense?

docker41 [41]3 years ago

6 0

Answer:

Step-by-step explanation:

6 + ( - 3)

Since a negative * a positive = a negative

6 - 3 = 3

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the length of a rectangle is 5ft more than twice the width and teh area of the rectabgle is 42ft squared. what are the dimension

lara [203]

The width is 3.5 and the length is 12

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3 years ago

What is 9. 24 repeating as a mixed number in simplest form?

Serga [27]

The recurring decimal number 9.2424... expressed in mixed number is $9\frac{24}{99}$

In the given decimal number, 2 is the digit at the tenth place and 4 is the digit at the hundredth place.

The fraction part $\frac{24}{99}$ in the simplest form is $\frac{8}{33}$

The whole number part is 9.

Therefore, the number 9.2424... as a mixed number in the simplest form is $9\frac{8}{33}$

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4 years ago

Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2

tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

1. 2x^2 - 7x + 3

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

a = 2
b = -7
c = 3

we can use the quadratic formula: $x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}$

Substitute the a, b, and c values into the quadratic formula: $x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}$

Now simplify using the laws of pemdas: $x=\frac{7\pm\sqrt{(49)-(24)} }{4}$

Simplify even further: $x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}$

Now split this equation into two equations to solve for x: $x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}$

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

$\boxed {x=3,\frac{1}{2} }$

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

x - 3 = 0
2x - 1 = 0

After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

2. 3x^2 + 7x + 2

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

3x + 1 = 0
x + 2 = 0

Solve.

First factor: 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

Second factor: x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

$\boxed {x = -\frac{1}{3} , -2}$

7 0

3 years ago

Which is the inverse of the function f(x)= x+3

tatuchka [14]

Answer is C
$let \: y \: = x + 3$
$make \: x \: subject \: of \: the \: formula$
$x = y - 3$

replace x with y above
$f {}^{ - 1} = x - 3$

4 0

3 years ago

Need Help finding the process for both of these ( due today)

Rzqust [24]

Similar triangles have side lengths that are proportional to each other. To find each of the missing lengths, we need to set up proportions.

The proportions will look as follows:

(length or unknown of triangle 1) / (length or unknown of triangle 2) = (length of triangle 1) / (length of triangle 2)

-On both sides, remember to be consistent with which length/unknown you put on top! If a triangle 1 length is the numerator on the left, then it also needs to be the numerator on the right! And this also works vice versa with triangle 2.

In each proportion equation, we can only have one unknown. On the left side of the equation, we choose one length or unknown of triangle 1, and the corresponding side length of unknown of triangle 2 (whichever you did not choose from triangle 1). On the right side of the equation, we use a completed proportion. This is because all of the sides of one triangle are proportional to the other triangle, but we need to know that proportion/ratio in order to find other side lengths.

Let's start with problem a, to show how this works:

Triangle 1 side lengths - 16, a, 11

Triangle 2 side lengths - 8, 3, b

As you can tell, the side lengths match up (corresponding!) on each triangle, as in they are in the same position on each triangle. Now, we will set up a proportion to find the length of side a on triangle 1.

a / 3 = 16 / 8

48 = 8a

a = 6

Next, let's find the length of side b on triangle 2.

11 / b = 16 / 8

16b = 88

b = 5.5

Moving on to problem b, we'll apply the same concept and steps from problem a in order to find the missing side lengths.

Triangle 1 side lengths: 5, 5.5, d

Triangle 2 side lengths: 15, c, 18

5 / 15 = 5.5 / c

5c = 82.5

c = 16.5

5 / 15 = d / 18

15d = 90

d = 6

Hope this helps!! :)

8 0

4 years ago

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