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3 years ago

1) A wave has a speed of 40 m/sec and a wavelength of

Physics

1 answer:

Vitek1552 [10]3 years ago

3 0

Answer:hmm not sure on that one

Explanation:

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Four importance of soil water

Andru [333]

Answer:

nitrogen, phosphorus, potassium, and calcium

Explanation:

Just put it.

4 0

2 years ago

WOULUJUTUL RECIPECUIUS.

3241004551 [841]

The force between the two objects is 19.73 nN.

<u>Explanation: </u>

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider $M_{1}$ and $M_{2}$ as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

$\text {Gravitational force}=\frac{G \times M_{1} \times M_{2}}{d^{2}}$

As gravitational constant $G=6.67 \times 10^{-11} \mathrm{m}^{3} \mathrm{kg}^{-1} \mathrm{s}^{-2}$ , $M_{1}$ = 20 kg and $M_{2}$ = 100 kg, while d = 2.6 m, then

$\text {Gravitational force}=\frac{6.67 \times 10^{-11} \times 20 \times 100}{(2.6)^{2}}=\frac{6.67 \times 20 \times 10^{-9}}{6.76}$

Thus, we get finally,

$\text {Gravitational force}=19.73 \times 10^{-9} \mathrm{N}$

As we know, nano denoted by letter 'n' equals to $10^{-9}$

So the force acting between two objects is 19.73 nN.

7 0

3 years ago

A bird sits on a high-voltage power line with its feet 3.87 cm apart. The wire is made from aluminum, is 2.11 cm in diameter, an

Svetlanka [38]

Answer:

ΔV=0.484mV

Explanation:

The potential difference across the end of conductor that obeys Ohms law:

ΔV=IR

Where I is current

R is resistance

The resistance of a cylindrical conductor is related to its resistivity p,Length L and cross section area A

R=(pL)/A

Given data

Length L=3.87 cm =0.0387m

Diameter d=2.11 cm =0.0211 m

Current I=165 A

Resistivity of aluminum p=2.65×10⁻⁸ ohms

ΔV=IR

$=I(\frac{pL}{A})\\ =I(\frac{pL}{\pi r^{2} } )\\=I(\frac{pL}{\pi (d/2)^{2} } )\\=165A((\frac{(2.65*10^{-8})(0.0387m)}{\pi (0.0211m/2)^{2} } ))\\=4.84*10^{-4}V$

ΔV=0.484mV

3 0

3 years ago

1. You have a cat who has a mass of 10 kg and is

disa [49]

Answer:

1) F = 100N

2) a = 2 m/s²

3) m = 25 kg

Explanation:

1) F = ma ( F = ?, m = 10 kg, a = 10 m/s² )

F = 10×10

F = 100 N

2) F = ma ( F = 20N, m = 10 kg, a = ? )

20 = 10×a

10a = 20

a = 20/10

a = 2 m/s²

3)F = ma ( F = 100N, m = ?, a = 4 m/s² )

100 = m×4

4m = 100

m = 100/4

m = 25 kg

Hope that helps! Good luck!

7 0

3 years ago

A Cepheid variable star is a star whose brightness alternately increases and decreases. Suppose that Cephei Joe is a star for wh

Maslowich

Time is being measured in days here so if you want to calculate the rate of increase after one day, substitute 1 for t in your rate equation:
dB/dt = 0.677598 cos(1.232(1))
dB/dt = 0.22

7 0

3 years ago