Hey! Apologies that I can’t make this look nice because I’m on mobile.
To simplify this, we can multiply the denominator by its conjugate. For a imaginary function (a+bi), its conjugate would be (a-bi), so we can apply that here to multiply both sides by (2-i)/(2-i). This works because it simplifies to one. Then, we have our fraction as 4*(2-i)/((2-i)(2+i))=(8-4i)/(4-i^2)=(8-4i)/5
Feel free to ask further questions, and have a great rest of your day!
Answer:
Step-by-step explanation:
498/26 = 19 with a remainder of 3
so each group will have nineteen students but you need 22 more to make all groups have 20 students
498 + 22 = 520
520/26= 20
Answer: 7238.28
Step-by-step explanation:
We are trying to find the number that when added to 19, gives us less than 42. We can set up this simple inequality:
19 + x < 42
Now, subtract 19 from both sides:
x < 23
Our number can be anything less than 23.
This is vague. Any dimensions that make a triangle can make more than one, just draw another right next to it. What's really being asked is which dimensions can make more than one non-congruent triangle.
<span>A. Three angles measuring 75°,45°, and 60°.
That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions. TRUE
<span>B. 3 sides measuring 7, 10, 12?
</span>Three sides determine the triangles size and shape uniquely; FALSE
<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>
40+50+60=150, no such triangle exists. FALSE
<em>D. 3 sides measuring 3,4,and 5</em>
Again, three sides uniquely determine a triangle's size and shape; FALSE
</span>
