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Step2247 [10]
3 years ago
7

Can you help me on this please

Physics
1 answer:
Vikentia [17]3 years ago
8 0

Answer: the water level would rise since the pebble displaces minimal water compared to the boat.

Explanation:..........

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On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per
Luda [366]

Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

Initial position = 60 km/h x 1 hour = 60 km

final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

V_{avg} = \frac{Final \ position\  - \ Initial \ position}{final \ time\  - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\  - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr

Therefore, the average velocity is 180 km/hr

3 0
3 years ago
Which type of electromagnetic radiation cannot be focused?
Irina18 [472]
The answer is A. Hope this helps. :)
7 0
3 years ago
Read 2 more answers
. A mass m is traveling at an initial speed of 25.0 m/s. It is brought to rest in a distance of 62.5 m by a net force of 15.0 N.
harkovskaia [24]

Answer:

m = 3 kg

The mass m is 3 kg

Explanation:

From the equations of motion;

s = 0.5(u+v)t

Making t thr subject of formula;

t = 2s/(u+v)

t = time taken

s = distance travelled during deceleration = 62.5 m

u = initial speed = 25 m/s

v = final velocity = 0

Substituting the given values;

t = (2×62.5)/(25+0)

t = 5

Since, t = 5 the acceleration during this period is;

acceleration a = ∆v/t = (v-u)/t

a = (25)/5

a = 5 m/s^2

Force F = mass × acceleration

F = ma

Making m the subject of formula;

m = F/a

net force F = 15.0N

Substituting the values

m = 15/5

m = 3 kg

The mass m is 3 kg

7 0
3 years ago
He __________ uses a series of gears to adjust the output speed of the engine.
Verizon [17]
Hey /人 ◕ ‿‿ ◕ 人\
The answer is transmission

uses a series of gears to transmit power to facilitate changes in speed .


GLAD TO HELP


~~~ ╔͎═͓═͙╗
~~~ ╚̨̈́═̈́﴾ ̥̂˖̫˖̥  ̂ )
4 0
3 years ago
Which method do acoustic use to limit reverberations in music halls
dalvyx [7]

Answer:

reverberation time appropriate to the use and size of the room, adequate balance between direct and reverberant sound, intimacy and good sound diffusion in the room to obtain a uniform sound.

Explanation:The process of ... second method measured the speed of sound propagation by the phase shift.

8 0
3 years ago
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