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emmainna [20.7K]
3 years ago
7

What is a variable that gives location relative to an origin?

Physics
2 answers:
lora16 [44]3 years ago
5 0

Answer:

The position variable gives location relative to an origin.

Explanation:

Position (displacement) gives location relative to an origin, but distance does not.

AysviL [449]3 years ago
4 0
The variable would be “X”
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A soccer player is running upfield at 10 m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleratio
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His acceleration would be 3.34 m/s 
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A solid cylinder is mounted above the ground with its axis of rotation oriented horizontally. A rope is wound around the cylinde
Romashka [77]

Answer:

(a)10.5 rad/s2

(b) 20.9 rev

(c) 47.27 m

Explanation:

As the block of mass 53 kg is falling and pulling on the rope. The tension force on the rope must be equal to the gravity acting on the block according to Newton's 3rd law

T = mg = 53*9.81 = 519.93  N

Since this tension force would rotate the cylinder freely without any friction. The torque created by this tension force is

To = TR = 519.93  * 0.36 = 187.17 Nm

This solid cylinder would have a moment of inertia around it's rotating axis of:

I = \frac{mR^2}{2} = \frac{275 * 0.36^2}{2} = 17.82kgm^2

(a)We can use Newton's 2nd law to calculate the angular acceleration exerted by such torque on the solid cylinder

\alpha = \frac{To}{I} = \frac{187.17}{17.82} = 10.5 rad/s^2

(b) With such constant angular acceleration, the angle it would make after 5s is

\theta = \frac{\alphat^2}{2} = \frac{10.5*5^2}{2} = 131.3 rad

Since each revolution equals to 2\pi rad of angle, we can calculate the number of revolution it makes

\frac{\theta}{2\pi} = \frac{131.3}{6.28} \approx 20.9 rev

(c) Assume the thickness of the rope is negligible (and its wounded radius is unchanging), we can calculate the rope length unwinded after rotating 131.3rad

\theta R = 131.3*0.36 = 47.27 m

3 0
3 years ago
A box rests on a horizontal, frictionless surface. a girl pushes on the box with a force of 17 n to the right and a boy pushes o
Komok [63]
Refer to the diagram shown below.

The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.

By definition,
Work = Force x Distance.

(a) The work done by the girl is
     W₁ = (17 N)*(3.5 m) = 59.5 J

(b) The work done by the boy is
     W₂ = (13 N)*(-3.5 m) = - 45.5 J

(c) The work done by the net force  is
    W₃ = (4 N)*(3.5 m) = 14 J

Note that W₃ = W₁ + W₂

Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J

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4 years ago
An airplane is cruising at a speed of 250 m/s. If the airplanes engines provide a forward force of 19,540 N, calculate the force
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Hope this helps you.

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