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Hitman42 [59]
4 years ago
14

Explain the difference between vehicular kinematics and occupant kinematics

Physics
2 answers:
belka [17]4 years ago
8 0
Vehicle Kinematics: a vehicle sliding sideways into a gravel pit, a vehicle driving down a bank, a vehicle driving up a ramp and a vehicle sliding laterally against a curb.  "sliding laterally against a curb" and "sliding sideways into a gravel pit".
Mariana [72]4 years ago
7 0

Answer:

We can find the difference using the definition of each concept.

First of all, kinematics refer to a subfield of classical mechanics that only DESCRIBES the motion of a body, point or any object.

Now, vehicular kinematics refer to the study of the motion of a vehicule, only to describe the movement. This subject is studied to test vehicules. Vehicular kinematics and vehicule dynamics are two important fields to analyse in vehicules production, to improvement them in case of accidents. It's important to specify that all these studies are only about the car itself.

On the other hand, we have occupant kinematics which refer to the study of the motion of the occupant who is inside the vehicle. This study is aimed to calculate the movement of the occupant in case of accidents, in order to prevent serious injuries. The best example for this is the air bag, which is an invention to prevent major injuries in case of accidents, this innovation was developed by analysing the motion of the occupant to see where the body goes and which part of the body hits the car inside. The air bag represents a simple but useful innovation that prevents many death per year in car accidents.

Therefore, basically, the difference between these two kinematics is that one studies the vehicle motion and the other one studies the occupant motion, the person inside the vehicle. These studies are important to develop and innovate new things to prevent accidents or serious injuries after an accident.

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a rocket engine can accelerate a rocket launched from rest vertically up with an acceleration of 22.9 m/s2. however, after 50.0
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The acceleration of a rocket engine is given here, and after 50 seconds of flight, the engine fails, and we must determine the altitude of the rocket at the time the engine fails.  Because the rocket starts from rest, the time taken is 50 seconds, the initial velocity is zero, and the acceleration is 22.9 meters per second square. So we use the kinamatics equation s equal to v. I t plus half 8 square. There is no acceleration at the start. 22.9 and t is 50 seconds, so displacement 2.86 times 10 to the power 4 is met. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

<h3>What exactly is accelerate?</h3>
  • In mechanics, acceleration is defined as the rate of change of an object's velocity with respect to time. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
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Hence, There is no acceleration at the start. 22. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

To know more about Accelerate refer to:

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3 0
1 year ago
2) The position of a particle is given r(t) = A(cos wt i + sin wt f), where w is a constant. (a) Show that the particle moves in
olya-2409 [2.1K]

Answer:

Explanation:

r(t) = A(cos wt i + sin wt f)

= A cos wt i + A sin wt j

x = A cos wt

y = A sin wt

radius r

r² = x² + y² ( This is equation of a circle with radius r  )

=  A² cos² wt +A² sin² wt

= A²

r = A

radius r = A

b )

speed = dr/dt

v = - Aw sinwt i + Aw coswt j

magnitude of velocity

I v I= Aw √(sin²wt + cos²wt)

= Aw ( constant )

acceleration

= dv / dt = - Aw² cos wt - Aw² sinwt

magnitude of acceleration

I a I = Aw²

= r w²

d ) centripetal force = m acceleration

m w² A  

=

7 0
3 years ago
A box is moved 2m across the floor with a force of 16n. How much work was done?
Nesterboy [21]

Answer:

 Work done on the box = 32 J

Explanation:

Work done = Force x Displacement.

Force applied on the box = 16 N

Displacement of box = 2 meter.

Work done on the box = Force applied on the box x  Displacement of box

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Work done on the box = 32 J

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