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Hitman42 [59]
3 years ago
14

Explain the difference between vehicular kinematics and occupant kinematics

Physics
2 answers:
belka [17]3 years ago
8 0
Vehicle Kinematics: a vehicle sliding sideways into a gravel pit, a vehicle driving down a bank, a vehicle driving up a ramp and a vehicle sliding laterally against a curb.  "sliding laterally against a curb" and "sliding sideways into a gravel pit".
Mariana [72]3 years ago
7 0

Answer:

We can find the difference using the definition of each concept.

First of all, kinematics refer to a subfield of classical mechanics that only DESCRIBES the motion of a body, point or any object.

Now, vehicular kinematics refer to the study of the motion of a vehicule, only to describe the movement. This subject is studied to test vehicules. Vehicular kinematics and vehicule dynamics are two important fields to analyse in vehicules production, to improvement them in case of accidents. It's important to specify that all these studies are only about the car itself.

On the other hand, we have occupant kinematics which refer to the study of the motion of the occupant who is inside the vehicle. This study is aimed to calculate the movement of the occupant in case of accidents, in order to prevent serious injuries. The best example for this is the air bag, which is an invention to prevent major injuries in case of accidents, this innovation was developed by analysing the motion of the occupant to see where the body goes and which part of the body hits the car inside. The air bag represents a simple but useful innovation that prevents many death per year in car accidents.

Therefore, basically, the difference between these two kinematics is that one studies the vehicle motion and the other one studies the occupant motion, the person inside the vehicle. These studies are important to develop and innovate new things to prevent accidents or serious injuries after an accident.

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Which type of communications equipment functions as a radio receiver and searches across several frequencies?
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7 0
2 years ago
A river flows due east at 1.60 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
Citrus2011 [14]

Answer:

part (a) v\ =\ 10.42\ at\ 81.17^o towards north east direction.

part (b) s = 46.60 m

Explanation:

Given,

  • velocity of the river due to east = v_r\ =\ 1.60\ m/s.
  • velocity of the boat due to the north = v_b\ =\ 10.3\ m/s.

part (a)

River is flowing due to east and the boat is moving in the north, therefore both the velocities are perpendicular to each other and,

Hence the resultant velocity i,e, the velocity of the boat relative to the shore is in the North east direction. velocities are the vector quantities, Hence the resultant velocity is the vector addition of these two velocities and the angle between both the velocities are 90^o

Let 'v' be the velocity of the boat relative to the shore.

\therefore v\ =\ \sqrt{v_r^2\ +\ v_b^2}\\\Rightarrow v\ =\ \sqrt{1.60^2\ +\ 10.3^2}\\\Rightarrow v\ =\ 10.42\ m/s.

Let \theta be the angle of the velocity of the boat relative to the shore with the horizontal axis.

Direction of the velocity of the boat relative to the shore.\therefore Tan\theta\ =\ \dfrac{v_b}{v_r}\\\Rightarrow Tan\theta\ =\ \dfrac{10.3}{1.60}\\\Rightarrow \theta\ =\ Tan^{-1}\left (\dfrac{10.3}{1.60}\ \right )\\\Rightarrow \theta\ =\ 81.17^o

part (b)

  • Width of the shore = w = 300m

total distance traveled in the north direction by the boat is equal to the product of the velocity of the boat in north direction and total time taken

Let 't' be the total time taken by the boat to cross the width of the river.\therefore w\ =\ v_bt\\\Rightarrow t\ =\ \dfrac{w}{v_b}\\\Rightarrow t\ =\ \dfrac{300}{10.3}\\\Rightarrow t\ =\ 29.12 s

Therefore the total distance traveled in the direction of downstream by the boat is equal to the product of the total time taken and the velocity of the river\therefore s\ =\ u_rt\\\Rightarrow s\ =\ 1.60\times 29.12\\\Rightarrow s\ =\ 46.60\ m

7 0
3 years ago
A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera
lana66690 [7]

Answer:

420000N

Explanation:

Given parameters:

Mass of the train  = 5.6 x 10⁵kg

Acceleration  = 0.75m/s²

Unknown:

Resultant force = ?

Solution:

According to newton's second law, force is the product of mass and acceleration;

   Force  = mass x acceleration

Resultant force that acts on the train is given below;

 Force  = 5.6 x 10⁵kg  x 0.75m/s²  = 420000N

7 0
3 years ago
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