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NemiM [27]
3 years ago
11

How many moles are there in 3.01 x 1024 atoms of argon?

Chemistry
1 answer:
Ahat [919]3 years ago
6 0

Answer:

Try this for answer 3082.24

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Answer: Molecules or substances that have tendency to donate electrons

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The "simple" hurdle that must be overcome to turn seawater into freshwater is to remove the dissolved salt in seawater. That may seem as easy as just boiling some seawater in a pan, capturing the steam and condensing it back into water (distillation).

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8 0
3 years ago
At what pH range bayer process operate? and why?
Novosadov [1.4K]

Explanation:

Bayer process is industrial method of the refining of the bauxite to produce alumina which is aluminum oxide.

As alumina is amphoteric in nature, it exhibits a higher solubility at both the extremes of pH range, it is possible to dissolve alumina in low as well as in high pH solutions.

Dissolution of the alumina at high pH is well recognized in Bayer process. Bauxite is digested in very <u>high pH solution (> 13)  of alkali</u> like sodium hydroxide at temperature of about 150–250°C and pressure at 20 atm. <u>This is done so that the dissolved alumina is separated from rest of insoluble bauxite minerals. </u>

3 0
4 years ago
A sodium bromide solution is added to a beaker containing aqueous chlorine. What would happen?
Darya [45]

Answer:

See detailed explanation.

Explanation:

Hello!

In this case, for the described chemical reaction, we can proceed as follows:

A) For the complete chemical reaction we note down every reacted and produced species as well as the proper balancing process:

2NaBr(aq)+Cl_2(aq)\rightarrow 2NaCl(aq)+Br_2(g)

In which gaseous bromine may give off.

B) The dissociated ionic equation requires the ionization of the aqueous species in ions, expect for chlorine which is not ionized:

2Na^+(aq)+2Br^-(aq)+Cl_2(aq)\rightarrow 2Na^+(aq)+2Cl^-(aq)+Br_2(g)

C) For the net ionic equation we cancel out the sodium ions as they are at both reactants and products:

2Br^-(aq)+Cl_2(aq)\rightarrow +2Cl^-(aq)+Br_2(g)

D) Based on C) we infer that the spectator ions here are the sodium ions.

Best regards!

6 0
3 years ago
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