Answer:
The answer to your question is P2 = 84.16 kPa
Explanation:
Data
Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l
Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?
Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C
Process
1.- Convert the temperature to °K
Temperature 1 = 23 + 273 = 296°K
Temperature 2 = -12 + 273 = 261°K
2.- Use the Combined Gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
-Substitution
P2 = (102)(4.52)(261) / (296)(4.83)
-Simplification
P2 = 120331.44 / 1429.68
-Result
P2 = 84.16 kPa
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.
<h3>What is Avogadro's law?</h3>
Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."
It is expressed as;
V₁/n₁ = V₂/n₂
Given the data in the question;
- Initial amount of gas n₁ = 5.4moles
- Initial volume v₁ = 34mL = 0.034L
- Final amount of gas n₁ = 6.2moles
We substitute our values into the expression above.
V₁/n₁ = V₂/n₂
V₁n₂ = V₂n₁
V₂ = V₁n₂ / n₁
V₂ = (0.034L × 6.2moles) / 5.4moles
V₂ = 0.2108molL / 5.4mol
V₂ = 0.039L
V₂ = 39 mL
Therefore, at constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.
Learn more about Avogadro's law here: brainly.com/question/15613065
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Answer:
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