The speed or the tangential velocity of the satellite to keep it in its orbit is 3,073.5 meters per second.
The gravitational force between two objects is given by:
F = GMm/r²
Where:
G = constant of gravity = 6.674 x 10⁻¹¹ N.m²/kg²
M, m = mass of each object
r = distance between objects
Parameters given in the problem:
M = 5.972 x 10²⁴ kg
m = 750 kg
r = 6371 + 35,800 = 42,171 km = 42,171,000 m
Hence,
F = 6.674 x 10⁻¹¹ x 5.972 x 10²⁴ x 750 / 42,171,000²
= 168.1 N
This is equal to centripetal force:
F = m . v² / r
168.1 = 750 . v² / 42,171,000
v² = 9,446,304
v = 3,073.5 m/s
Hence, the tangential velocity of the satellite to keep it in its orbit is 3,073.5 m/s
Learn more about gravitational force here:
brainly.com/question/23504494
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