Given:
The angle of projection of the basketball, θ=35°
The height at which the ball leaves the hand, h=7 ft
The initial velocity of the basketball, v=20 ft/s
To find:
The parametric equations describing the shot.
Explanation:
The range, x of the basketball is given by,
On substituting the known values,
The change in the height, y of the basketball is given by,
Where g is the acceleration due to gravity.
On substituting the known values,
Final answer:
The parametric equations describing the shot are
Answer:
Incident Command Structure, ICS or ICS-like EOC Structure is familiar and aligns with the on-scene incident organization. ICS or ICS-like EOC Structure is familiar and aligns with the on-scene incident organization.
Answer: a. boiler - I. part of a coal-fired power plant.
b. combustion chamber - I. part of a coal-fired power plant.
c. condenser - III. part of a coal-fired power plant and part of a nuclear power plant.
d. control rod - I. part of a coal-fired power plant.
e. generator- III. part of a coal-fired power plant and part of a nuclear power plant.
f. turbine - III. part of a coal-fired power plant and part of a nuclear power plant.
Explanation:
a. Boiler: It is used in the coal power plant to heat the water used for producing electricity. The boiler keeps the temperature of water or steam at a desired level.
b. Combustion chamber: It is used for combustion of coal and using thermal energy for electricity generation.
c. Condenser; It is used in both nuclear and coal power plants. It condense and receive from the turbine.
d. Control rod: It is used in the nuclear power plant for controlling the nuclear fission and fusion reactions of heavy metals.
e. Generator: It converts the thermal energy into electrical energy.
f. Turbine: The turbine blades move with the effect of steam or any form of energy and the energy so produce is used for generating electricity in generator.
Answer:
v1=21.81m/s
Explanation:
<em>When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g golf ball at rest on a tee. Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 44 m/s. Neglect the mass of the club handle and determine the speed (in m/s) of the golf ball just after impact.</em>
According to the law of conservation of momentum, if the net external force on a system is zero, then the linear momentum of the system is conserved.
During collision of two particles, the external force on the system of two colliding particles is zero (only internal force acts between the colliding particles), therefore, the momentum is conserved during the collision.
Answer and Explanation:
Given :
head of the golf club=160g
velocity of the golf club=50 m/s
golf ball mass=46g
velocity=om/s
m1u1+m2u2=m1v1+m2v2.........................................1
160*50 +46*0=160*44+46*v1
8000=7040+46v1
960=46v1
v1=960/46
v1=21.81m/s
The equivalent of Newton's second law for rotational objects is given by:
where
is the net torque acting on the object
is its moment of inertia
is its angular acceleration
For a hoop rotating around its perpendicular axis, the moment of inertia is
where m is the mass and r the radius. By using the data of the wheel, m=0.750 kg and r=33.0 cm=0.33 m, we find
and since the torque is
, the angular acceleration of the wheel is
