Answer:
To have a 100% chance of having offspring with the recessive genotype, each parent's genotype must be homozygous recessive.
Explanation:
For a recessive trait to be phenotypically evident it is necessary that the two alleles that form it are recessive, that is, that they are recessive homozygous.
The presence of a single dominant allele in one parent will probably suppress the expression of the recessive gene in at least half of the offspring.
<u>For the offspring to be 100% recessive, both parents must have a homozygous recessive genotype</u>.
Learn more:
Dominance principle brainly.com/question/13735349
The menstrual<span> cycle </span>occurs<span> due to the rise and fall of hormones</span>
Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
Answer:
They are all built of chemically linked monomers.
Answer:
Eukaryotes are organisms made out of eukaryotic cells, cells with a membrane-bound nucleus and membrane-bound organelles.
Prokaryotes differ from eukaryotes in that their cells do not contain a membrane-bound nucleus that contains their DNA.
Explanation:
