Answer:
![x^2 + \frac{1}{49} =1](https://tex.z-dn.net/?f=%20x%5E2%20%2B%20%5Cfrac%7B1%7D%7B49%7D%20%3D1%20)
And solving for x we got:
![x^2 = 1- \frac{1}{49}](https://tex.z-dn.net/?f=%20x%5E2%20%3D%201-%20%5Cfrac%7B1%7D%7B49%7D)
![x^2 = \frac{48}{49}](https://tex.z-dn.net/?f=%20x%5E2%20%3D%20%5Cfrac%7B48%7D%7B49%7D)
And taking square root we got:
![x = \sqrt{\frac{48}{49}}= \frac{\sqrt{48}}{7} = \frac{4\sqrt{3}}{7}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Csqrt%7B%5Cfrac%7B48%7D%7B49%7D%7D%3D%20%5Cfrac%7B%5Csqrt%7B48%7D%7D%7B7%7D%20%3D%20%5Cfrac%7B4%5Csqrt%7B3%7D%7D%7B7%7D)
Step-by-step explanation:
For this case we have the following point given ![P(x , -1/7)](https://tex.z-dn.net/?f=%20P%28x%20%2C%20-1%2F7%29)
And we want to find the value of x, since P lies on the unitray circle if we find the distance from P to the center of the unitary circle (0,0) we need to get 1. Using the definition of Euclidean distance that means:
![d = \sqrt{(x -0)^2 +(-1/7 -0)^2}=1](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B%28x%20-0%29%5E2%20%2B%28-1%2F7%20-0%29%5E2%7D%3D1)
And if we square both sides of the last equation we got:
![x^2 + \frac{1}{49} =1](https://tex.z-dn.net/?f=%20x%5E2%20%2B%20%5Cfrac%7B1%7D%7B49%7D%20%3D1%20)
And solving for x we got:
![x^2 = 1- \frac{1}{49}](https://tex.z-dn.net/?f=%20x%5E2%20%3D%201-%20%5Cfrac%7B1%7D%7B49%7D)
![x^2 = \frac{48}{49}](https://tex.z-dn.net/?f=%20x%5E2%20%3D%20%5Cfrac%7B48%7D%7B49%7D)
And taking square root we got:
![x = \sqrt{\frac{48}{49}}= \frac{\sqrt{48}}{7} = \frac{4\sqrt{3}}{7}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Csqrt%7B%5Cfrac%7B48%7D%7B49%7D%7D%3D%20%5Cfrac%7B%5Csqrt%7B48%7D%7D%7B7%7D%20%3D%20%5Cfrac%7B4%5Csqrt%7B3%7D%7D%7B7%7D)
Answer:
C. ![| v -21 | \leq 0.15](https://tex.z-dn.net/?f=%7C%20v%20-21%20%7C%20%5Cleq%20%200.15)
Step-by-step explanation:
Because the volume is either 0.15 more or 0.15 less than 21 ounces.
indicate the difference between the volume and 21 and it has to be less than 0.15. Therefore answer C.
89 tenths......................
Answer:
2.3554335e+42
Step-by-step explanation: