First we find the interquartile range which is Q3 (third quartile) - Q1 (first quartile)
so the IQR = 52 - 32 = 20
now u multiply ur IQR by 1.5
20 * 1.5 = 30
now subtract that from Q1 and add that to Q3
32 - 30 = 2....so anything below 2 is an outlier
52 + 30 = 82...and anything above 82 is an outlier
so ur outlier is : 83
10% of of $48 is an additional discount of $4.80.
Rocco's friend will have to pay $43.20 for the putter.
All reals is the answer.
Since y =-9 graph is way below the absolute value graph. Meaning that y value of modulus is greater than the constant graph.
Answer:
a1=-3 a2=-12 a3=-72 a4=-576 a5=-5760
Step-by-step explanation:
Answer:
The p-value of the test is 0.2.
Step-by-step explanation:
Using the alternative hypothesis that µ ≠ 531, Amy found a t-test statistic of 1.311.
Alternative hypothesis means that e have a two-tailed hypothesis test.
Sample 30 citizens. Amy found a t-test statistic of 1.311.What is the p-value of the test statistic?
Thus, we have a two-tailed test with 30 - 1 = 29 degrees of freedom and t = 1.311. So, using a t-distribution calculator, the p-value of the test is 0.2.
