Answer:
A kilogram describes how much matter an object contains
Answer:
t = 94.91 nm
Explanation:
given,
wavelength of the light = 522 nm
refractive index of the material = 1.375
we know the equation
c = ν λ
where ν is the frequency of the wave
c is the speed of light
ν = 5.75 x 10¹⁴ Hz
the thickness of the coating will be calculated using
t = 94.91 nm
the thickness of the coating will be equal to t = 94.91 nm
Answer:
y = 54.9 m
Explanation:
For this exercise we can use the relationship between the work of the friction force and mechanical energy.
Let's look for work
W = -fr d
The negative sign is because Lafourcade rubs always opposes the movement
On the inclined part, of Newton's second law
Y Axis
N - W cos θ = 0
The equation for the force of friction is
fr = μ N
fr = μ mg cos θ
We replace at work
W = - μ m g cos θ d
Mechanical energy in the lower part of the embankment
Em₀ = K = ½ m v²
The mechanical energy in the highest part, where it stopped
= U = m g y
W = ΔEm = - Em₀
- μ m g d cos θ = m g y - ½ m v²
Distance d and height (y) are related by trigonometry
sin θ = y / d
y = d sin θ
- μ m g d cos θ = m g d sin θ - ½ m v²
We calculate the distance traveled
d (g syn θ + μ g cos θ) = ½ v²
d = v²/2 g (sintea + myy cos tee)
d = 9.8 12.6 2/2 9.8 (sin16 + 0.128 cos 16)
d = 1555.85 /7.8145
d = 199.1 m
Let's use trigonometry to find the height
sin 16 = y / d
y = d sin 16
y = 199.1 sin 16
y = 54.9 m
Answer:
37500 J
Explanation:
Law of conservation of energy: Its states that energy can neither be created nor destroyed but it can be transformed from one form to another.
Applying the law of conservation of energy.
The change in kinetic energy for the truck = Net work done by the truck skids
ΔK.E = F×d.................... Equation 1
Where ΔK.E = Change in kinetic energy, F = Force, d = distant.
Given: F = 1500 N, d = 25 m
Substitute these values into equation 1
ΔK.E = 1500×25
ΔK.E = 37500 J
Explanation:
Below is an attachment containing the solution.