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3 years ago

5

A temperature inversion can adversely affect air quality and is characterized by ________

1 answer:

balandron [24]3 years ago

8 0

A layer of warm air forming above colder air!

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Which part of the female reproductive system produces ova?

vovangra [49]

A would be the best answer beacuse
Ovaries - small, oval-shaped glands that are located on either side of the uterus. The ovaries produce eggs (ova - an ovum is one egg, ova means multiple eggs.) The ovaries also produce the main female sex hormones which are released into the bloodstream.

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3 years ago

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What is the effect on an electric current when the voltage is increased? An increase in voltage causes the flow of electric curr

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A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of ac

lions [1.4K]

Answer:

x = 95 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} =v_{o} +a*t$

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

Now we can find the acceleration

19 = 0 *a*(10)

a = 1.9 [m/s]

With the second equation we can find the distance:

$v_{f} ^{2} =v_{o} ^{2} +(2*a*x)$

where:

x = distance [m]

(19)² = (0)² + (2*1.9*x)

3.8*x = 361

x = 95 [m]

7 0

3 years ago

Two spherical objects are separated by a distance of 2.59 × 10-3 m. The objects are initially electrically neutral and are very

kodGreya [7K]

Answer:

Number of electrons, n = 12 electron

Explanation:

Given that,

The distance between charged spheres, $d=2.59\times 10^{-3}\ m$

The object experiences an electrostatic force that has a magnitude of, $F=4.94\times 10^{-21}\ N$

The electric force between spheres is given by :

$F=\dfrac{kq^2}{d^2}$

$q=\sqrt{\dfrac{Fd^2}{k}}$

$q=\sqrt{\dfrac{4.94\times 10^{-21}\times (2.59\times 10^{-3})^2}{9\times 10^9}}$

$q=1.91\times 10^{-18}\ C$

Let there are n number of electrons. Using quantization of electric charge we get :

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{1.91\times 10^{-18}}{1.6\times 10^{-19}}$

n = 11.93 electrons

or

n = 12 electrons

Hence, 12 electrons produce the charge on one of the objects.

4 0

3 years ago

A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the vel

Murljashka [212]

Answer:

8.5m/s

Explanation:

We are given that

Mass of object=m=0.50 kg

Initial velocity, u=0

Force=F=2.88 N

Time=1.48 s

a.We know that

$F=ma$

Using the formula

$2.88=0.50a$

$a=\frac{2.88}{0.50}=5.76m/s^2$

$a=\frac{v-u}{t}$

Using the formula

$5.76=\frac{v-0}{1.48}$

$v=5.76\times 1.48=8.5m/s$

Hence, the velocity of the object at the end of this time interval=8.5m/s

8 0

3 years ago