V = 8 * 10^2 km/h = 800km/h
S= 1,8* 10^3 km = 1800km
t = ?
v = S/t
t = S/v
t = 1800km/ 800km/h
t ≈ 2,25h (135min)
1) Equivalent resistance, 1/R = 1/15 + 1/40 + 1/60 = 8+3+2 /120 = 13/120
R = 120/13 = 9.23
2) Current, I = V/R = 115/9.23 = 12.45 A
Answer:
q=6.22*10^-10C
Explanation:
Two large metal plates of area 0.88 m2 face each other, 4.8 cm apart, with equal charge magnitudes but opposite signs. The field magnitude E between them (neglect fringing) is 80 N/C. Find |q|
E=α/∈, electric field within the plate
α=q/A
A=area of the plate
∈=is the permittivity
substituting , we have
The field magnitude E between them (neglect fringing)
E=q/A∈
q=EA∈
q=0.88*80*8.84*10^-12
q=6.22*10^-10C
Answer:
s = 3.84 x 10⁸ m
Explanation:
The distance traveled by an object, while in uniform motion, is given by the following equation:
s = vt
where,
s = distance covered
v = speed
t = time interval
In this case:
s = distance between Moon and Earth = ?
v = speed of radio waves = 3 x 10⁸ m/s
t = time taken to travel = 1.28 s
Therefore,
s = (3 x 10⁸ m/s)(1.28 s)
<u>s = 3.84 x 10⁸ m</u>
