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zhannawk [14.2K]
3 years ago
12

A trolley has a mass of 1.2 kg and a speed of 4.5 m/s. The trolley crashes into a stationary trolley of mass 0.8 kg. On impact t

he two trolleys stick together and move off with speed, v. Calculate the momentum of the trolleys before impact. Calculate the speed of the trolleys after impact.
Physics
1 answer:
attashe74 [19]3 years ago
8 0

(a) The momentum of the first trolley is 5.4 kgm/s

(b) The velocity of the trolleys after impact is 2.7m/s

<u>Explanation:</u>

Given:

Mass, m₁ = 1.2kg

Velocity, v₁ = 4.5m/s

Mass, m₂ = 0.8kg

v₂ = 0

(a) Momentum of the trolley before impact, p

We know:

Momentum = mass X velocity

p = 1.2 X 4.5

p = 5.4 kgm/s

Therefore, the momentum of the first trolley is 5.4 kgm/s

(b) Speed of the trolleys after impact, v = ?

During collision, the momentum is conserved.

So,

m₁v₁ + m₂v₂ = (m₁ + m₂)v

(1.2 X 4.5) + (0.8 X 0) = (1.2 +0.8) X v

5.4 + 0 = 2v

v = 2.7m/s

Therefore, the velocity of the trolleys after impact is 2.7m/s

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\left |  \vec{R}\right |=\sqrt{a^2+b^2+2ab\cos \theta}

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The type of rocks that once existed in these  locations are limestone and dolomite whereas the pH of the nearby groundwater is slightly acidic which is responsible for the formation of caves. Caves are formed by the dissolution of limestone due to acid rain.

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(a) Since m_{3} is placed midway between m_{1} and m_{2}, then its distance to both masses is 0.170 m.

From the Newton's law of universal gravitation,

F = \frac{Gm_{1}m_{2}  }{r^{2} }

Where all variables have their usual meaning.

Then,

a. F_{net} = F_{23} - F_{13}

F_{13} = \frac{6.67*10^{-11}*165*60 }{(0.17)^{2} }

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(ii) /F_{net}/ = /F_{23}/ - /F_{13}/

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(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.

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