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mash [69]
3 years ago
12

Good night India and good morning USA​

Chemistry
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

Mornin'!

Explanation:

(Actually, it's the afternoon over where I am.)

maks197457 [2]3 years ago
3 0

Answer:

yes, there is a time difference according to the different time zones. It is about 10 hours and 30 minutes change according to India and Washington D.C

Explanation:

You might be interested in
The sulfur content of an ore is determined gravimetrically by reacting the ore with concentrated nitric acid and potassium chlor
katen-ka-za [31]

Answer:

13.92 %

Explanation:

Mass of BaSO_4 = 12.5221 g

Molar mass of BaSO_4 = 233.43 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{12.5221\ g}{233.43\ g/mol}

Moles of BaSO_4 = 0.0536 moles

According to the given reaction,

Ba^{2+}_{(aq)}+SO_4^{2-}_{(aq)}\rightarrow BaSO_4_{(s)}

1 mole of BaSO_4 is formed from 1 mole of SO_4^{2-}

Thus,

0.0536 moles of BaSO_4 is formed from 0.0536 moles of SO_4^{2-}

Moles of SO_4^{2-} = 0.0536 moles

Moles of sulfur in 1 mole SO_4^{2-} = 1 mole

Moles of sulfur in 0.0536 mole SO_4^{2-} = 0.0536 mole

Molar mass of sulfur = 32.065 g/mol

Mass = Moles * Molar mass = 0.0536 * 32.065 g = 1.7187 g

Mass of ore = 12.3430 g

Mass % = \frac{Mass\ of\ Sulfur}{Mass_{ore}}\times 100 = \frac{1.7187}{12.3430}\times 100 = 13.92 %

3 0
4 years ago
What besides genes influences traits? PLEASE HELP!
Nat2105 [25]
Traits are determined by alleles.
4 0
3 years ago
Calculate the amount of heat needed to boil 183.g of ethanol ( CH3CH2OH ), beginning from a temperature of 33.9°C . Round your a
Shkiper50 [21]

Answer:

19,700 Joules

Explanation:

Quantity of heat (Q) = mc(T2-T1)

m (mass of ethanol) = 183g

c (specific heat capacity of ethanol) = 2.44J/g°C

T2 (boiling temperature of ethanol) = 78°C

T1 (initial temperature of ethanol) = 33.9°C

Q = 183×2.44(78 - 33.9) = 183×2.44×44.1 = 19691.532 = 19,700 Joules (to three significant digits)

6 0
3 years ago
How many formula units of CaO are in 32.7 g of CaO?
zhuklara [117]

Answer:

D) 3.51x10²³ formula units

Explanation:

To know this, we need to calculate the molecular mass of CaO. To do that, let's use the atomic mass of each element of this compound.

Ca: 40.08 g/mol;    O: 16 g/mol

With these given AM, let's calculate the molar mass of CaO:

Mm CaO = 40.08 + 16 = 56.08 g/mol

Now that we have the MM of CaO, it's time to determine the moles of CaO:

moles = mass / MM

moles = 32.7 / 56.08 = 0.5831 moles

Finally to get the formula units, we need to use the Avogadro's number which is 6.02x10²³. According to this number, 1 mole of any substance has this number of atoms, molecules or formula units. So, if we have 0.5831 moles, then the formula units will be:

FU = 0.5831 * 6.02x10²³

<h2>FU = 3.51x10²³ formula units</h2>

Hope this helps

7 0
3 years ago
A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrat
Nana76 [90]

Answer:

<u> </u><u>85.952 ml</u> Zn^2^+  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of CoSO_4 =\frac{Given mass }{molar mass}

                                                       =\frac{1.817}{155}

                                                          =0.01172

Molarity = \frac{no. of moles}{volume of solution}

           =\frac{0.01172}{20}

        =0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

                            = 0.009005 - 0.000586

                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 (Zn^2^+)

           0.008419\times100ml=0.009795\times V2

           V2=\frac{0.008419\times100}{0.009795}

             V2 =85.952 ml

Therefore , <u>85.952 ml </u>Zn^2^+ needed to titrate the excess complexing reagent .

3 0
3 years ago
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