Answer:
13.92 %
Explanation:
Mass of
= 12.5221 g
Molar mass of
= 233.43 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of
= 0.0536 moles
According to the given reaction,

1 mole of
is formed from 1 mole of 
Thus,
0.0536 moles of
is formed from 0.0536 moles of 
Moles of
= 0.0536 moles
Moles of sulfur in 1 mole
= 1 mole
Moles of sulfur in 0.0536 mole
= 0.0536 mole
Molar mass of sulfur = 32.065 g/mol
Mass = Moles * Molar mass = 0.0536 * 32.065 g = 1.7187 g
Mass of ore = 12.3430 g
Mass % =
=
= 13.92 %
Traits are determined by alleles.
Answer:
19,700 Joules
Explanation:
Quantity of heat (Q) = mc(T2-T1)
m (mass of ethanol) = 183g
c (specific heat capacity of ethanol) = 2.44J/g°C
T2 (boiling temperature of ethanol) = 78°C
T1 (initial temperature of ethanol) = 33.9°C
Q = 183×2.44(78 - 33.9) = 183×2.44×44.1 = 19691.532 = 19,700 Joules (to three significant digits)
Answer:
D) 3.51x10²³ formula units
Explanation:
To know this, we need to calculate the molecular mass of CaO. To do that, let's use the atomic mass of each element of this compound.
Ca: 40.08 g/mol; O: 16 g/mol
With these given AM, let's calculate the molar mass of CaO:
Mm CaO = 40.08 + 16 = 56.08 g/mol
Now that we have the MM of CaO, it's time to determine the moles of CaO:
moles = mass / MM
moles = 32.7 / 56.08 = 0.5831 moles
Finally to get the formula units, we need to use the Avogadro's number which is 6.02x10²³. According to this number, 1 mole of any substance has this number of atoms, molecules or formula units. So, if we have 0.5831 moles, then the formula units will be:
FU = 0.5831 * 6.02x10²³
<h2>
FU = 3.51x10²³ formula units</h2>
Hope this helps
Answer:
<u> </u><u>85.952 ml</u>
needed to titrate the excess complexing reagent .
Explanation:
Lets calculate
After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml
As the number of moles of
=
=
=0.01172
Molarity = 
=
=0.000586 moles
Excess of EDTA = concentration of EDTA - concentration of CoSO4
= 0.009005 - 0.000586
= 0.008419 M
As M1V1 ( Excess of EDTA ) = M2V2 


V2 =85.952 ml
Therefore , <u>85.952 ml </u>
needed to titrate the excess complexing reagent .