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lesya692 [45]
3 years ago
13

A certain liquid X has a normal boiling point of 111.20 celsius and a boiling point elevation constant Kb=0.95. calculate the bo

iling point of a solution made of 11. g of ammonium chloride dissolved in 400 g of X.
Chemistry
1 answer:
Goshia [24]3 years ago
8 0

Answer: the boiling point is = 137.325°C

Explanation:

From the formula: ∆Tb= Kb*m

From the question, Kb= 0.95, m= 27.5, T1= 111.2°C

Substitute into ∆Tb= Kb*m

∆Tb= 0.95*27.5= 26.125

∆Tb= T2-T1

Hence

T2- 111.2=26.125

T2= 26.125+ 111.2= 137.325°C

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What is the molar concentration (molarity) of a solution made by dissolving 0.285 moles of CaCl2(s) in just enough water to form
marusya05 [52]

Answer:

The answer to your question is Molarity = 0.238

Explanation:

Data

Molarity = ?

number of moles = 0.285

volume = 1.2 L

Molarity is a unit of concentration that relates the moles of a substance by the volume in liters.

Formula

Molarity = moles / volume

Substitution

Molarity = 0.285 / 1.2

Simplification and result

Molarity = 0.238

7 0
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Explanation:

3 0
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zimovet [89]

Explanation:

For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.

For example, CH_{3}CH_{2}OH, CH_{3}NH_{2} and NH_{3} all these compounds contain an electronegative atom attached to hydrogen atom.

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4 0
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Answer:

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Have a nice day!

4 0
3 years ago
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