Find the inverse of h(x)= -x^5+2 step by step

Mathematics

1 answer:

nikdorinn [45]2 years ago

6 0

Hi there!

$\large\boxed{y = \sqrt[5]{-(x-2)}}$

$h(x) = -x^{5} + 2$

Rewrite h(x) as y:

$y = -x^5 + 2$

Switch the x and y variables:

$x = -y^{5} + 2$

Isolate y by subtracting 2 from both sides:

$x - 2 = -y^5$

Multiply both sides by -1:

$-(x-2) = y^5$

Take the 5th root of both sides:

$y = \sqrt[5]{-(x-2)}$

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