Answer:
Vertical distance= 3.3803ft
Explanation:
First with the speed of the ball and the distance traveled horizontally we can determine the flight time to reach the plate:
Velocity= (90 mi/h) × (1 mile/5280ft) = 475200ft/h
Distance= Velocity × time⇒ time= 60.5ft / (475200ft/h) = 0.00012731h
time= 0.00012731h × (3600s/h)= 0.458316s
With this time we can determine the distance traveled vertically taking into account that its initial vertical velocity is zero and its acceleration is that of gravity, 9.81m/s²:
Vertical distance= (1/2) × 9.81 (m/s²) × (0.458316s)²=1.0303m
Vertical distance= 1.0303m × (1ft/0.3048m) = 3.3803ft
This is the vertical distance traveled by the ball from the time it is thrown by the pitcher until it reaches the plate, regardless of air resistance.
Answer:

Explanation:
Given that
The speed of the airplane ,v= 142 m/s
The speed of the air ,u = 30 m/s
Lets take angle make by airplane from east direction towards north direction is θ .
Now by using diagram ,we can say that

Now by putting the values in the above equation we get



Therefore the angle will be 12.19° .
The force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:
To solve this exercise the formulas and procedures we will use are:
- v(x) = v * cosine (angle)
- v(y) = v * sine (angle).
Where:
- v= magnitude of the vector
- v(x) = component of the vector on the (x) axis
- v(y) = component of the vector on the (y) axis
- angle = angle
Information about the problem:
- angle = 60º
- v = 12.0 N
- v(x)= ?
- v(y)= ?
Applying the formula of the component of the vector in the (x) axis we have:
v(x) = v * cosine (angle).
v(x) = 12.0 N * cosine (60º)
v(x) =6 N
Applying the formula of the component of the vector in the (y) axis we have:
v(y) = v * sine (angle)
v(y) = 12.0 N * sine (60º)
v(y) = 10.39 N
<h3>What is a vector?</h3>
It can be said to be a straight line described by a point (a) and (b) that has direction and sense.
Learn more about vector at: brainly.com/question/2094736
#SPJ4
Known variables
d=4.6m
initial velocity=0m/s
downward acceleration=-9.8m/s2
d=1/2gt2
4.6=1/2 -9.8 t2
t=0.93s
This is true. Not sure what you're looking for as an answer. But this would be true, you have to pay the deductible before a company will pay. EXCEPT in the case that it's not your fault and the other driver is paying.