For the answer to the question above,
<span>There is nothing in the equations to suggest that the string moves in the x direction so D) v_x(x,t)=0.
</span>
y(x,t) = A sin(kx-omega t)
d{y(x,t)}/d{x} = A k cos(kx - omega t)
Alexander Calders mobiles, like untitled, move when air currents move through them, making them kinetic. Alexander Calder was an American artist, famous for his abstract sculpture, hanging mobiles, and Kinetic art. Kinetic art is the <span>art that depends on motion for its effect. The kinetic art's works of Alexander Calders were called "mobiles".</span>
Answer:
0.015m^3
Explanation:
1 m^3 = 1000 liters
x m^3 = 15 liters
Cross multiply
xm^3 x 1000 l = 15 l
Divide both sides by 1000
xm^3 x1000/1000 = 15/1000
xm^3 = 0.015m^3
Therefore 15 liter = 0.015m^3
Answer:
a) wet marble , dry marble, newspaper, and towel
Answer:
Al llegar a su equilibrio térmico ambas barran tendrán una temperatura de 53 grados centígrados.
Explanation:
Dado que una barra de aluminio que está a 78 grados centígrados entra en contacto con una barra de cobre de la misma longitud y área que esta a 28 grados centígrados, y posteriormente se lleva acabo la transferencia de energía entre ambas barras llegando a su equilibrio térmico, para determinar la temperatura a la que ambas barras llegarán se debe realizar el siguiente cálculo:
(78 + 28) / 2 = X
106 / 2 = X
53 = X
Por lo tanto, al llegar a su equilibrio térmico ambas barran tendrán una temperatura de 53 grados centígrados.
