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tiny-mole [99]
3 years ago
7

Which best describes reflection and refraction? Waves change direction when encountering boundaries in reflection but not in ref

raction.
Waves change direction when encountering boundaries in refraction but not in reflection.

Waves change direction when encountering boundaries in both reflection and refraction.

Waves do not change direction when encountering boundaries in either reflection or refraction.


ANSWER: Waves change direction when encountering boundaries in both reflection and refraction.
Physics
2 answers:
Radda [10]3 years ago
9 0

Answer :Waves change direction when encountering boundaries in both reflection and refraction.

Explanation:

zmey [24]3 years ago
4 0

When a wave bounces off a barrier and changes direction that is called reflection. Refraction, however occurs when a wave changed mediums, so if a wave were to go from moving in air to moving in water, the wave would change a direction that is based upon the index of refraction of that given medium.

So, if the answer is classifying a medium as a "boundary" then yes, they both change direction, however, a physical boundary only causes a change in direction in reflection.

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1. A 100-kg crate is pulled across a warehouse floor using a rope with a force of 250 N at an angle of 45o from the horizontal.
harkovskaia [24]

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Explanation:

Given;

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applied force, F = 250 N

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coefficient of friction, μ = 0.12

Applied force in y-direction, F_y = Fsin \theta = 250sin45 = 176.78 \ N

Applied force in x-direction, F_x = Fcos \theta = 250cos45 = 176.78 \ N

The normal force is calculated as;

N + Fy -W = 0

N = W - Fy

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The frictional force is given by;

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Fk = 0.12 x 803.22

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F_{net} = F_x - F_k\\\\F_{net} = 176.78-96.386\\\\F_{net} = 80.394 \ N

Apply Newton's second law of  motion;

F = ma

a = \frac{F_{net}}{m}\\\\ a = \frac{80.394}{100}\\\\ a = 0.804 \ m/s^2

(b) the velocity of the crate after 5.0 s

F = ma= \frac{m(v-u)}{t} \\\\Ft =m(v-u)\\\\v-u = \frac{Ft}{m}\\\\ v = \frac{Ft}{m} + u\\\\v = \frac{F_{net}*t}{m} + u\\\\v = \frac{80.394*5}{100} + 1\\\\v = 5.02 \ m/s

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