Answer:
Your teacher is out of her/his mind, what is he thinking
Explanation:
my dear friend, i feel sorry for you, poor thing T_T
Answer:
a) t₁ = 4.76 s, t₂ = 85.2 s
b) v = 209 ft/s
Explanation:
Constant acceleration equations:
x = x₀ + v₀ t + ½ at²
v = at + v₀
where x is final position,
x₀ is initial position,
v₀ is initial velocity,
a is acceleration,
and t is time.
When the engine is on and the sled is accelerating:
x₀ = 0 ft
v₀ = 0 ft/s
a = 44 ft/s²
t = t₁
So:
x = 22 t₁²
v = 44 t₁
When the engine is off and the sled is coasting:
x = 18350 ft
x₀ = 22 t₁²
v₀ = 44 t₁
a = 0 ft/s²
t = t₂
So:
18350 = 22 t₁² + (44 t₁) t₂
Given that t₁ + t₂ = 90:
18350 = 22 t₁² + (44 t₁) (90 − t₁)
Now we can solve for t₁:
18350 = 22 t₁² + 3960 t₁ − 44 t₁²
18350 = 3960 t₁ − 22 t₁²
9175 = 1980 t₁ − 11 t₁²
11 t₁² − 1980 t₁ + 9175 = 0
Using quadratic formula:
t₁ = [ 1980 ± √(1980² - 4(11)(9175)) ] / 22
t₁ = 4.76, 175
Since t₁ can't be greater than 90, t₁ = 4.76 s.
Therefore, t₂ = 85.2 s.
And v = 44 t₁ = 209 ft/s.
I believe it’s B but i’m not sure
Newton’s second law is a=F/m this is what we will be using to solve this
However first you need to convert g to kg
100g= 0.1kg
0.05/0.1=0.5 m/s^2
Answer:
P_2 = 1.62 atm
Explanation:
We know the formula for the rms speed of the ideal gas is given by
P= pressure of the surrounding
V= volume of the vessel
m= mass of the gas
Now, From this formula rms speed (v_rms) is directly proportional to square root is pressure.
Then
given that v_rsm,1= v0
and v_rsm,2=0.9v0
putting these values we get
P_2 = 1.62 atm
