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tiny-mole [99]
3 years ago
7

Which best describes reflection and refraction? Waves change direction when encountering boundaries in reflection but not in ref

raction.
Waves change direction when encountering boundaries in refraction but not in reflection.

Waves change direction when encountering boundaries in both reflection and refraction.

Waves do not change direction when encountering boundaries in either reflection or refraction.


ANSWER: Waves change direction when encountering boundaries in both reflection and refraction.
Physics
2 answers:
Radda [10]3 years ago
9 0

Answer :Waves change direction when encountering boundaries in both reflection and refraction.

Explanation:

zmey [24]3 years ago
4 0

When a wave bounces off a barrier and changes direction that is called reflection. Refraction, however occurs when a wave changed mediums, so if a wave were to go from moving in air to moving in water, the wave would change a direction that is based upon the index of refraction of that given medium.

So, if the answer is classifying a medium as a "boundary" then yes, they both change direction, however, a physical boundary only causes a change in direction in reflection.

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Marcus tries to move a refrigerator but can't. Has he done work?
katen-ka-za [31]

Answer:

A

Explanation:

Even if the refrigerator did not move he still used energy to try to push it it's just his energy wasnt stronger than the refrigerator's energy

3 0
3 years ago
Determine the angle between the directions of vector a = 3.00i 1.00j and vector b = 1.00i 3.00j .
Katena32 [7]

The angle between the two vectors is 126° 52' 11".

The given parameters;

vector A = 3.00i + 1.00j

vector B = 1.00i + 3.00j

The angle between the two vectors is calculated as follows;

cos  \theta = \frac{A.B}{|A|.|B|}

The dot product of vectors A and B is calculated as;

A.B = ( 3i + 1j ) . ( 1i +3j )

      = ( 3 × 1 ) + ( 1  × 3 )

      = 3 + 3

      = 6

The magnitude of vectors A and B is calculated as;

|A|  = \sqrt[]{3^2 + 1^2} = \sqrt[]{10} \\

|B| = \sqrt[]{1^2 + 3^2} = \sqrt[]{10} \\

The angle between in two vectors is calculated as;

Cos \theta = \frac{6}{\sqrt[]{10}\sqrt[]{10}  } \\\\Cos \theta = \frac{6}{\ 10 }\\\\Cos \theta = 0.6\\\\\theta = cos^-^1 (0.6)\\\\\theta = 126\\

Therefore, the angle between the two vectors is 126° 52' 11".

Learn more about vectors here:

brainly.com/question/25705666

#SPJ4

6 0
2 years ago
How does a black hole form
Shtirlitz [24]
A black hole forms when the center of a very massive star collapses in upon itself.
3 0
3 years ago
Read 2 more answers
Consider horizontal parallel plates with a fixed potential difference. The upper plate has a voltage difference of 30 V with the
BlackZzzverrR [31]

relation between potential difference and electric field is given as

E . d = \Delta V

so here we know that

d = 3 cm

\Delta V = 30 V

E \times 0.03 = 30

E = 1000 N/C

So now when plates are separated to 4 cm distance carefully

the potential difference between them will change but the electric field between them will remain constant

So at distance of 4 cm also the electric field will be E = 1000 N/C

5 0
3 years ago
if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?
Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,  

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

0=19+10 \times t

-19=10 \times t

\frac{-19}{10}=t

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

\text { Consider the equation } V^{2}-U^{2}=2 a S

Solving the equation we will get the value of S

0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }

-361 = -20S

Negative sign cancel both the sides.

\mathrm{S}=\frac{361}{20}

S = 18.05 m

Maximum height is 18.05 m  .

3 0
3 years ago
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