If it's not moving at all at the beginning of the 10 seconds, then it falls 490 meters straight down in 10 seconds.
(Note: This is true of all objects on Earth . . . rubber balls, feathers, grains of sand, school buses, battle ships . . . everything. As long as air doesn't hold them back. Anything falling from rest falls 490 meters in the first 10 seconds.)
Answer:
48kg
Explanation:
i could be wrong if i am srry
Answer:
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
Explanation:
given data
glider A mass = 0.125 kg
glider B mass = 0.500 kg
glider A move = 0.960 m to the left
solution
we use here Conservation of momentum that is
M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2 ........................1
put here value and we get
0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB
VB = −0.32 m/s
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
Answer:
The change in height of the mercury is approximately 2.981 cm
Explanation:
Recall that the formula for thermal expansion in volume is:
from which we solved for the change in volume 
due to a given change in temperature 
We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:
Therefore, the change in volume with a change in temperature of 36°C becomes:
Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):
No se porque?
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