<span>Answer:
Molecular:
HC2H3O2(aq) + KOH(aq) --> KC2H3O2(aq) + H2O(l)
Complete ionic:
HC2H3O2(aq) + K+(aq) + OH-(aq) --> K+(aq) + C2H3O2-(aq) + H2O(l)
Net Ionic:
HC2H3O2(aq) + OH-(aq) --> C2H3O2-(aq) + H2O(l)</span>
How much hydrogen chloride acid was used?
72.916 g of hydrochloric acid was used.
Given:
Mass of Zn = 65.39 g
Mass of 
=136.29 g
Mass of 
= 2 g
Equation:
The chemical equation for the reaction of zinc with hydrochloric acid:
Zn + 2HCl → Zn 
+
Hydrogen gas is created when zinc combines with hydrochloric acid, which causes the process to bubble ferociously. Another sign that a chemical reaction is taking place is the generation of a gas.
Calculation:
A number of equivalents equate:
Number of equivalents = 
x 1000 x equivalent factor
x 1000 x 1 = 
x 1000 x 2
= 36.458 x 2
= 72.916
Learn more about the calculation of mass here,
brainly.com/question/21290034
#SPJ4
Answer:
Option D is correct = 58 g
Explanation:
Data Given:
mass of LiOH = 120 g
Mass of Li3N= ?
Solution:
To solve this problem we have to look at the reaction
Reaction:
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol 3 mol
Convert moles to mass
Molar mass of LiOH = 24 g/mol
Molar mass of Li₃N = 35 g/mol
So,
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol (35 g/mol) 3 mol (24 g/mol)
35 g 72 g
So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of LiOH
For this apply unity formula
35 g of Li₃N ≅ 72 g of LiOH
X of Li₃N ≅ 120 g of LiOH
By Doing cross multiplication
Mass of Li₃N = 35 g x 120 g / 72 g
mass of Li₃N = 58 g
120 g of LiOH will produce from 58 g of Li₃N
So,
Option D is correct = 58 g
Answer:
108.43 grams KNO₃
Explanation:
To solve this problem we use the formula:
Where
- ΔT is the temperature difference (14.5 K)
- Kf is the cryoscopic constant (1.86 K·m⁻¹)
- b is the molality of the solution (moles KNO₃ per kg of water)
- and<em> i</em> is the van't Hoff factor (2 for KNO₃)
We <u>solve for b</u>:
- 14.5 K = 1.86 K·m⁻¹ * b * 2
Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:
- 275 mL water ≅ 275 g water
- moles KNO₃ = molality * kg water = 3.90 * 0.275
- moles KNO₃ = 1.0725 moles KNO₃
Finally we <u>convert KNO₃ moles to grams</u>, using its molecular weight:
- 1.0725 moles KNO₃ * 101.103 g/mol = 108.43 grams KNO₃
Idk if it's correct but I guess it's calcite (c)
