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otez555 [7]
3 years ago
9

The coefficient of volume expansion of a certain olive oil is 0.68 × 10-3 K-1. A 1.0-L glass beaker is filled to the brim with o

live oil at room temperature. The beaker is placed on a range and the temperature of the oil and beaker increases by 25 C°. As a result, 0.0167 L of olive oil spills over the top of the beaker. Which of the following values is closest to the coefficient of linear expansion of the glass from which the beaker is made?
a. 4 × 10-6 K^-1
b. 2 × 10-5 K^-1
c. 3 × 10-5 K^-1
d. 1 × 10-5 K^-1
e. 1 × 10-6 K^-1

Physics
1 answer:
natita [175]3 years ago
4 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra
lukranit [14]

Answer:

\frac{dA}{dt} = 28800 \ m^2/year

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

  • Area of a Rectangle: A = lw

<u>Algebra I</u>

  • Exponential Property: w^n \cdot w^m = w^{n + m}

<u>Calculus</u>

Derivatives

Differentiating with respect to time

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Explanation:

<u>Step 1: Define</u>

Area is A = lw

2w = l

w = 300 m

\frac{dw}{dt} = 24 \ m/year

<u>Step 2: Rewrite Equation</u>

  1. Substitute in <em>l</em>:                    A = (2w)w
  2. Multiply:                              A = 2w²

<u>Step 3: Differentiate</u>

<em>Differentiate the new area formula with respect to time.</em>

  1. Differentiate [Basic Power Rule]:                                                                   \frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}
  2. Simplify:                                                                                                           \frac{dA}{dt} = 4w\frac{dw}{dt}

<u>Step 4: Find Rate</u>

<em>Use defined variables</em>

  1. Substitute:                    \frac{dA}{dt} = 4(300 \ m)(24 \ m/year)
  2. Multiply:                        \frac{dA}{dt} = (1200 \ m)(24 \ m/year)
  3. Multiply:                        \frac{dA}{dt} = 28800 \ m^2/year
3 0
3 years ago
Read 2 more answers
a boat traveling at a speed of 1.63 m / s has a kinetic energy of 52000 J what is the mass of the boat
BARSIC [14]

Answer:

39,098‬ kg

Explanation:

KE = .5 * m * v^2

52000=.5m * 1.63^2

52000=.5m * 2.66

52000/2.66=.5m

19,549 = .5m

19549/.5 = m

m=39,098‬ kg

5 0
3 years ago
Three identical train cars, coupled together are rolling east at 2.0 m/s. A fourth car traveling east at 4.0 m/s catches up with
Ann [662]

Answer:

The value is  v  =  2 \ m/s

Explanation:

From the question we are told that

   The velocity of the each of the three cars is u_1 = u_2 = u_3 =  2 \  m/s

    The velocity of the fourth car is  u_4 =  4 \ m/s

    The initial velocity of the fifth car u_5 =  0 \ m/s

Generally from the law of momentum conservation we have that

    m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 =  [m_1   + m_2 + m_3 +m_4+ m_5]v

Given that the cars are identical then their mass will be the same

i.e

    m_1 =m_2 = m_3 = m_4 = m_5 =  m

=>   [u_1 + u_2 +  u_3 +u_4 + u_5]m =  5mv

=>   2+ 2 +  2 +4 + 0 =  5v

= >   v  =  2 \ m/s

8 0
3 years ago
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JulijaS [17]

Answer:

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Explanation:

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7 0
3 years ago
Vector A, with magnitude 28.0 units, points in the positive y-direction. Vector A + B has a magnitude of 19.0 units and points i
Leokris [45]
<h2>Answer:</h2>

|B|  = 47.0 units

<h2>Explanation:</h2>

The sum of two vectors (A) and (B) gives another vector (A + B). i.e

(A + B) = (A) + (B)       ----------------(i)

<em>From the question;</em>

Vector A = 28.0 units in the positive y-direction. This means that the value of the x-component is zero and the value of the y-component is +28

In unit vector notation vector A is given as;

A = 0i + 28.0j

Vector A + B = 19.0 units in the negative y-direction. This means that the value of the x-component is zero and the value of the y-component is -19.0

In unit vector notation, vector A + B is given as;

A + B = 0i - 19.0j

To get the magnitude of vector B, make B the subject of the formula in equation (i) as follows;

(B) = (A + B) - (A)            ------------------ (ii)

Substitute the values of the vectors (A) and (A + B) into equation (ii) as follows;

(B) = (0i - 19.0j) - (0i + 28.0j)

(B) = - 19.0j - 28.0j

(B) = - 47.0j

The magnitude of B, |B|, is therefore;

|B| = |-47.0|

|B| = 47.0 units

8 0
4 years ago
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