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Usimov [2.4K]
2 years ago
11

=

Mathematics
1 answer:
prohojiy [21]2 years ago
3 0
I try and try and I can’t seem to make up bro it’s like I knew she was cheating but I didn’t have the heart to confront her bro I loved her bro I had to take cares him I did it for us bro I did it for us bro all he had to do was stay away
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What is the ratio of rolling a 2 to rolling a 5?
soldi70 [24.7K]

Answer:

when we have two dice, the odds are not as simple. For example, there's only one way to roll a two (snake eyes), but there's a lot of ways to roll a seven (1+6, 2+5, 3+4).

Step-by-step explanation:

got em

7 0
3 years ago
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Which expression is equivalent to -4(w-1)<br><br>4w-4<br>4w<br>-4w+4 <br>-5w<br>None of the above
dimulka [17.4K]

Answer:

-4w+4

Step-by-step explanation:

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3 years ago
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In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
5 (i + 2) = 8 (i -1)
Vinil7 [7]
5(i + 2) = 8(i -1)
5i + 10 = 8i -8
-3i + 10 = -8
-3i = -18
i = 6
5 0
3 years ago
How do you do this....
Angelina_Jolie [31]

Answer:

Answer is "No real Solution"

4 0
3 years ago
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