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2 years ago

What is the meaning of the reference point in electric potential?.

Physics

1 answer:

mrs_skeptik [129]2 years ago

4 0

Answer:

<h3><u>ELECTRIC POTENTIAL</u></h3>

• the amount of work needed to move a unit charge from a reference point to a specific point against an electric field.

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How is energy and work related.<br>

Anna007 [38]

Answer:

Varies

Explanation:

They both relate to the process of doing something.

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3 years ago

Read 2 more answers

A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it

natka813 [3]

Answer:

$t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}$

Explanation:

The rotated angle is given by:

$\theta=\omega0*t+1/2*\alpha*t^2$

Since this is a quadratic equation it can be solved using:

$x=\frac{-b \± \sqrt{b^2-4*a*c} }{2*a}$

Rewriting our equation:

$1/2*\alpha*t^2+\omega0*t-\theta=0$

$t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}$

Since $\sqrt{\omega0^2+2*\theta*\alpha} >\omega0$ we discard the negative solution.

$t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}$

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3 years ago

Does earths Roation causes gravity?

gogolik [260]

Answer:

he gravity of Earth, denoted by g, is the net acceleration that is imparted to objects due to the combined effect of gravitation (from mass distribution within Earth) and the centrifugal force (from the Earth's rotation )

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3 years ago

You're in a car that gets 37 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and

Sergeu [11.5K]

Answer:

Required diameter of hose pipe = 0.2864 mm

Solution:

From the continuity eqn, the fluid flow rate is given by:

Av = $\frac{V}{t}$

where

A = cross-sectional area = $\pi r^{2}$

r = hose pipe radius

v = velocity of gas

Also, $v = \frac{displacement, d}{time, t}$

Using:

1 gallon = 3.854 l

1 mile = 1609.34 m

$1 m^{3} = 1000 l$

Therefore,

$A\frac{d}{t} = \frac{V}{t}$

$\pi r^{2} = \frac{V}{d}$

$\pi r^{2} = \frac{(1 gal).(\frac{3.7854 l}{gal}).(\frac{10^{- 3} m^{3}}{l})}{37 miles(\frac{1609.34 m}{miles})}$

$6.357\times 10^{- 8} = \pi r^{2}$

$r^{2} = 2.024\times 10^{- 8}$

$r = 1.423\times 10^{- 4} m = 0.1423 mm$

The diameter of the hose pipe = 2r = $2\times 1.423\times 10^{- 4}$

The diameter of the hose pipe = $2.846\times 10^{- 4} m = 0.2846 mm$

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3 years ago

You are walking along a small country road one foggy morning and come to an intersection. while you are crossing, you hear an am

monitta

You're hearing a higher frequency than the sound that's actually coming from the siren on the ambulance, so it must be moving TOWARD you.

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4 years ago