I'm not gonna write 200-500 words, but, it's balanced because both side have the same number of elements. this relates to law of conservation of matter bc both sides are equal.
hope this helped!!
<h3><u>Answer;</u></h3>
= 78 g of NaOH
<h3><u>Explanation;</u></h3>
Concentration = Moles of solute/Volume of solution
Thus;
Moles of the solute = Volume × Concentration
= 7.80 Moles/L × 0.250 L
= 1.95 moles
But; 1 mole of NaOH = 40.0 g
Thus;
Mass of NaOH = moles × molar mass
= 1.95 moles × 40 g/mole
<u> = 78 g of NaOH</u>
Answer:
A is second order
B is first order.
![V=k[A]^{2} [B]](https://tex.z-dn.net/?f=V%3Dk%5BA%5D%5E%7B2%7D%20%5BB%5D)
![k=1.12](https://tex.z-dn.net/?f=k%3D1.12)
Explanation:
<u>order of the reaction with respect to A</u>
<u>
</u>
<u>
</u>
Then V∝![[A]^{2}](https://tex.z-dn.net/?f=%5BA%5D%5E%7B2%7D)
<u>order of the reaction with respect to B</u>
<u>
</u>
<u>
</u>
Then V∝![[B]}](https://tex.z-dn.net/?f=%5BB%5D%7D)
<u>Rate law of the reaction</u>
![V=k[A]^{2}[B]](https://tex.z-dn.net/?f=V%3Dk%5BA%5D%5E%7B2%7D%5BB%5D)
<u>Rate constante of the reaction</u>
![k=\frac{V}{[A]^{2}[B]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7BV%7D%7B%5BA%5D%5E%7B2%7D%5BB%5D%7D)
![k=1.12](https://tex.z-dn.net/?f=k%3D1.12)