Potassium carbonate, K2CO3, sodium iodide, NaI, potassium bromide, KBr, methanol, CH3OH, and ammonium chloride, NH4Cl, are solub
just olya [345]
Answer:
A. K₂CO₃
Explanation:
The chemical reaction showing the ions produced on dissolving Potassium carbonate in water is:
K₂CO₃ ⇒ 2K⁺ + CO₃²⁻
Number of ions produced = 2 + 1 = 3
The chemical reaction showing the ions produced on dissolving sodium iodide in water is:
NaI ⇒ Na⁺ + I⁻
Number of ions produced = 1 + 1 = 2
The chemical reaction showing the ions produced on dissolving potassium bromide in water is:
KBr ⇒ K⁺ + Br⁻
Number of ions produced = 1 + 1 = 2
The chemical reaction showing the ions produced on dissolving ammonium chloride in water is:
NH₄Cl ⇒ NH₄⁺ + Cl⁻
Number of ions produced = 1 + 1 = 2
<u>The largest number of dissolved particles per mole of dissolved solute is produced by Potassium carbonate.</u>
An ocean ridge is an underwater mountain system which is the result of tectonic plate movement. Its formation involves two processes: ridge-push and slab pull. The former occurs when the growing bulk of the ridge pushes the rest of the tectonic plate away from the ridge. Oftentimes, they go towards a subduction zone. In this zone, the latter, which is the slab pull comes into effect. This is the weight of the tectonic plate subducted or pulled down below the overying plate tagging along the rest of the plate behind it.
They are generally located halfway between two continents.
Explanation:
2,6-Dibromo-4-isopropylphenol
2432-16-8
2,6-dibromo-4-propan-2-ylphenol
Phenol, 2,6-dibromo-4-(1-methylethyl)-
4-isopropyl-2,6-dibromophenol
Answer:
2.51 Angstroms
Explanation:
For a particle in a one dimensional box, the energy level, En, is given by the expression:
En = n²π² ħ² / 2ma²
where n is the energy level, ħ² is Planck constant divided into 2π, m is the mass of the electron ( 9.1 x 10⁻³¹ Kg ), and a is the length of the one dimensional box.
We can calculate the change in energy, ΔE, from n = 2 to n= 3 since we know the wavelength of the transition ( ΔE = h c/λ ) and then substitute this value for the expresion of the ΔE for a particle in a box and solve for the length a.
λ = 207 nm x 1 x 10⁻⁹ m/nm = 2.07 x 10⁻⁷ m ( SI units )
ΔE = 6.626 x 10⁻³⁴ J·s x 3 x 10⁸ m/s / 2.07 x 10⁻⁷ m
ΔE = 9.60 x 10⁻¹⁹ J
ΔE(2⇒3) = ( 3 - 2 ) x π² x ( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )
9.60 x 10⁻¹⁹ J = π² x( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )
⇒ a = 2.51 x 10⁻¹⁰ m
Converting to Angstroms:
a = 2.51 x 10⁻¹⁰ m x 1 x 10¹⁰ Angstrom / m = 2.51 Angstroms
So molarity which is represented by that 0.01M refers to the amount of moles that is present in 1L or 1dm³ of the substance, in this case the acid. Molarity refers to CONCENTRATION therefore and has little to do with the strength of the acid (the strength is dependent on the pH).
Thus your answer is OPTION B
