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ruslelena [56]
3 years ago
10

When aqueous solutions of HCl and NaOH are mixed together in a calorimeter, the temperature of the solution increases. The react

ion is
endothermic, causing an increase in the kinetic energy of the solute particles.

endothermic, causing an increase in the kinetic energy of the water molecules.

(exothermic, causing an increase in the kinetic energy of the water molecules.)
exothermic, causing an increase in the kinetic energy of the solute particles.
Chemistry
1 answer:
yarga [219]3 years ago
6 0
This reaction is exothermic because the system (the aqueoud solution) is transferring heat to its surroundings (the calorimeter) so this eliminates two responses. Since the heat is being transferred to the surroundings, the water that's in the calorimeter in this case, it is causing the water molecules to heat up and thus an increase in the kinetic energy of the water molecules since temperature affects kinetic energy
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fredd [130]

Answer:

1,063 grams H₃PO₄

Explanation:

To find the mass of phosphoric acid (H₃PO₄), you should (1) convert molecules to moles (via Avogadro's number) and then (2) convert moles to grams (via molar mass from periodic table).

Molar Mass (H₃PO₄): 3(1.008 g/mol) + 30.974 g/mol + 4(15.998 g/mol)

Molar Mas (H₃PO₄): 97.99 g/mol

6.534 x 10²⁴ molecules H₃PO₄                       1 mole                         97.99 g
---------------------------------------------  x  -------------------------------------  x  --------------
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= 1,063 grams H₃PO₄

3 0
1 year ago
The burning of a sample of propane
r-ruslan [8.4K]

Answer:

70.0°C

Explanation:

We are given;

  • Amount of heat generated by propane as 104.6 kJ or 104600 Joules
  • Mass of water is 500 g
  • Initial temperature as 20.0 ° C

We are required to determine the final temperature of water;

Taking the initial temperature is x°C

We know that the specific heat of water is 4.18 J/g°C

Quantity of heat = Mass × specific heat × change in temperature

In this case;

Change in temp =(x-20)° C

Therefore;

104600 J = 500 g × 4.18 J/g°C × (x-20)

104600 J = 2090x -41800

146400 = 2090 x

  x = 70.0479

     =70.0 °C

Thus, the final temperature of water is 70.0°C

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7 0
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