Answer:
<em> </em><em>here </em><em>9</em><em>*</em><em>1</em><em>0</em><em>^</em><em>4</em><em> </em><em>is </em><em>a </em><em>square </em><em>number </em>
Step-by-step explanation:
<em>9</em><em>*</em><em>1</em><em>0</em><em>^</em><em>4</em><em> </em><em>=</em><em> </em><em>9</em><em>0</em><em>0</em><em>0</em><em>0</em>
<em>and </em><em>it </em><em>is </em><em>a </em><em>square </em><em>of </em><em>3</em><em>0</em><em>0</em><em> </em>
Answer:
ma'am or sir... there is no picture attached... but whats the question?
Step-by-step explanation:
Answer:
pota pota pota thats the song
We see that CF and DE are parallel to each other, which means that they had the same length with each other, so:
6n-1=5n+9
Subtract 5n for both side
6n-1-5n=5n+9-5n
n-1=9
Add 1 for both side
n-1+1=9+1
n=10
CF=
6n-1
=6(10)-1
=60-1
=59
DE=
5n+9
=5(10)+9
=50+9
=59
CD/FE:
4n+2
=4(10)+2
=42
True/False:
n=10 True
n=7 False
CF=59 True
FE=42 True
CD=30 False. As a result, n=10;CF=59; and FE=42 is your final answer. Hope it help!