Please solve with explanation
1 answer:
Answer:
a)x+69+73=180°{sum of angle of triangle}
b)
let, another a unknown side be 'p'
p=65°{alternate angle}
65+65+z=180°{sum of angle of triangle.}let ule
130+z=180
z=180-130
z=50°
- y+z+65°=180°{straight angle}
- y+115=180°
- y=180-115
- y=65°
z=x{alternate angle.}
x=50°
so, x=50°, y=65°, z=50°
c)z+19°=180°{straight angle}
z=180-19
z=161°
- z=y{co_interior angle}
- y=161°
d) 67+35+x=180°
x=180-102
x=78°
- y+67=180°{straight angle}
- y=180-67
- y=113°
- 35+z=180°{straight angle}
- z=180-35
- z=145°
2)
3x+10+2x-5+x-5=180°{sum of angle of triangle}
6x=180°
x=180/6
x=30°
hope it helps.
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