Question

Please solve with explanation

Answer 1

Answer:

a)x+69+73=180°{sum of angle of triangle}

• 142+x=180
• x=180-142
• x=38°

b)

let, another a unknown side be 'p'

p=65°{alternate angle}

65+65+z=180°{sum of angle of triangle.}let ule

130+z=180

z=180-130

z=50°

• y+z+65°=180°{straight angle}
• y+115=180°
• y=180-115
• y=65°

z=x{alternate angle.}

x=50°

so, x=50°, y=65°, z=50°

c)z+19°=180°{straight angle}

z=180-19

z=161°

• z=y{co_interior angle}
• y=161°

d) 67+35+x=180°

x=180-102

x=78°

• y+67=180°{straight angle}
• y=180-67
• y=113°

• 35+z=180°{straight angle}
• z=180-35
• z=145°

2)

3x+10+2x-5+x-5=180°{sum of angle of triangle}

6x=180°

x=180/6

x=30°

hope it helps.