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ehidna [41]
2 years ago
14

In at least 4 complete sentences, describe the similarities and differences between Avogadro's Law and Charles' Law.

Chemistry
1 answer:
viktelen [127]2 years ago
7 0

answer

Avogadro's law states that, at constant temperature and pressure, the volume of a gas is directly proportional to the number of moles present. In other words, equal volumes of gases at the same pressure and temperature contain the same number of molecules - this is true regardless of their physical properties or chemical nature.

This number of molecules is

6.022

⋅

10

23

and is known as Avogadro's number,

N

A

.

Matematically, Avogadro's law can be written like this

V

n

=

c

o

n

s

t

, or, better yet,

V

1

n

1

=

V

2

n

2

.

Avogadro's law, as well as Boyle's law and Charles' law, are special cases of the ideal gas law,

P

V

=

n

R

T

. If temperature and pressure are kept constant, and knowing that

R

is of course constant, then

P

V

=

n

R

T

→

P

V

n

=

R

T

→

V

n

=

R

T

P

=

c

o

n

s

t

, which represents Avogadro's law.

The ideal gas law can also be written to incorporate

N

A

, since the number of moles are actually the number of molecules divided by Avogadro's number

P

V

=

N

N

A

⋅

R

T

, where

N

represents the number of molecules.

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Five calcite, CaCO3 (MM 100.085 g/mol), samples of equal mass have a total mass of 12.2±0.1 g . What is the average mass and abs
Westkost [7]

Answer:

  • <em>The average mass of calcium in each sample is: </em><u>0.978 g</u>

<em />

  • <em>The absolute uncertainty is: </em><u>0.008 g</u>

Explanation:

The <em>absolute uncertainty </em>of the total samples indicated in the statement is ± 0.1 g.

When you multiply or divide quantities with uncertainties, you calculate the final uncertanty by adding the <em>relative uncertainties</em> together.

The relative uncertainty is the absolute uncertainty divided by the quantity:

  • Relative uncertainty = 0.1g / 12.2 g = 0.008

The average mass of calcium is calculated using proportions, along with the molar masses:

  • Molar mass of calcium: 40.078 g/ mol (from a periodic table)

  • Molar mass of calcite: 100.085 g/mol (given)

Proportion:

  • 40.078 g of calcium / 100.085 g of calcite = x / 12.2 g of calcite

  • x = 12.2 × 40.078 / 100.085 g = 4.89 g calcium

So the total mass of calcium in the five samples is 4.89 g, and the average mass in each sample is:

  • Average mass = total mass of five samples / number of samples

  • Average mass = 4.89 g / 5 = <u>0.978 g of calcium</u>

So, the first answer is that the average mass of calcium in each sample is 0.978 g ( keep 3 signficant figures, such as the quntitiy 12.2 shows, as  you have only used multiplication and division).

The absolute uncertainty of each sample is the relative uncertainty multiplied by the average mass of calcium of the five samples, rounded to one decimal:

  • Absolute uncertainty = 0.978 g × 0.008 ≈ 0.008 g

The answer to the secon question is that the absolute uncertaingy of calcium in each sample is 0.008 g.

7 0
3 years ago
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